Re: xCalendar

Hi Dave

Thanks for the answer. That is what I did, but I thought that there is possible an event (function) such as $$calendar.current.wkday as in the case with the time internal variable.

Regards.

Frans
=======================================================

--- In [email protected], dazroo <daz4roo@...> wrote:
>
> On 23/07/10 15:31, Marianne wrote:
> >
> >
> > All users
> >
> > I need help with the above mentioned control.
> >
> > With the time internal variable it is possible to get the day of a week
> > that is $$time.wkday. My question is how can I get the day of the week
> > when a person clicked on the xCalendar control.
> >
> > There are internal variables such as $$calendar.current.month day or year.
> >
> > Is there a work around.
> >
> > Regards.
> >
> > Frans
> >
> 
> Hi Frans,
> 
> In the absence of anything better, I'd get the weekday by converting
> the date returned to Julian, then take its modulo 7 ($jday % 7).
> 
> Like this:
> 
> 	wd0 = 'Monday'
> 	wd1 = 'Tuesday'
> 	wd2 = 'Wednesday'
> 	wd3 = 'Thursday'
> 	wd4 = 'Friday'
> 	wd5 = 'Saturday'
> 	wd6 = 'Sunday'
> 
> 	date = "23/7/2010"  // <-- e.g. from xCalendar
> 
> 	Extract date JULIAN jday
> 	wday = $($jday % 7)
> 
> 	say ' date = $date : weekday = $wday ($wd$wday)'
> 
> 
> // date = 23/7/2010 : weekday = 4 (Friday)
> 
> 
> Hope that helps,
> 
> Dave
>




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