[o-o-o-oo-o-o-o][o-o-o-oo-o-o-o] Quantum relativity o.i!!i.o - redefining numbers;

[+o+]

Hi friends,

this issue is very urgent so I'm writing you again. I closed my
website, left HTTP not working. I will define it later. When I can I
will make a much better everything - speedy communication, mail,
everything - not depending on me and will keep working without me -
completely open for changes - like Linux. If you want to help please
do; but I need more people whom I can trust. If you want to be my
friends, you or your friends then please use my public keys, create
your own (human readable) public keys and introduce yourselves. When I
have time I will maybe create a platform for doing this - in the
meantime please do it manually. I also need money but this is urgent
and I can't start a new job right now. If you can't encrypt and don't
trust computers, then please send me a paper mail - I need to know who
you are personally.

I thought about it, pitagoran and fermat were both right - they
defined numbers and math the way they wanted it to be, so in THEIR
math of course they are both right - they will both me wrong in my
quantum math - I will prove this. I will also show you why a binary
computer will never be able to understand math. Turing knew this,
actually he worked for the USA Army and everything related to Turing,
his recursively testing himself, my splitting my personality (more
than twice - not such a number) - this is all related to the 1905-1945
conspiracy / 2005-1945 backword conspiracy / 1984-1948 BBIAWY etc. I
will explain this. But first, a new matrix:

abcd
efgh
ijkl
mnst
opuv
wxyz
// wrote this ommitting some letters, left this, have to check why.

abcd / -[0123] / אבגד / alpha betta gamma delta : allways five letters!
efgh / 0123 / הוזח
ijkl / 0123 // sounds like "i!!! jeuu kiii llll youuu" / יייי
mnop / 0123 // "klmn"-->"כלום" ; hebrew: כלמנ
qrst / 0123 // קרשת or קרסט
uvwx // 0123 // sounds "you vve double[vvee] you!! exit!
yz // yez!zevel! // -2; -1;

the letter "T" (capital t) in the two is of course number 15 which is
not surprising at all! (counting from e0; otherwise 20 counting from
a1); and 1111 binary; also in matrix:

[e;f;g;h] [0;1;2;3] [0000;0001;0010;0011]
[i;j;k;l] [0;1;2;3] [0100;0101;0110;0111]
[m;n;o;p] [0;1;2;3] [1000;1001;1010;1011]
[q;r;s;t] [0;1;2;3] [1100;1101;1110;1111]

the letter "T" (as in "True") is the largest number, right/down for me
(jew; 5 fingers); then next matrix:

[u;v;w;x;y;z] [0;1;2;3;4;5] [1;2;3;4;5;6]

"w" means twice "v" (pronouced "double "u", spelled "double v"); "u"
is the first letter in this matrix, 0 or 1 (depends how you count),
then v is "straighing" u and the "double v / double u";

then o; of course "the o"; but not ASCII 0, of course. I will explain
it later. In english when you say "o" (have been in south africa) or
write "o" you always mean "0" and not "one";

n: nine;
e: Aleph; elef; efes; oooo [==0000]; אמת ("emet")

i: 0100(four) in english; ten in hebrew י; actually 10base10 (binary /
decimal) and 0100 means the same thing, I will explain this. for now,
just think you can't have positive 10 and negative 10 represented both
as the 10 can you? how do you count twenty? or even 10+10? you
cann't!!!

OK, enough for the matrix for now. let's just say "two" is a three
letter word and I will replace it with "ttt" for computers who are not
friendly with me. they will have to replace it again. BUT I want to
tell you - it's an imaginary number! there is no such a "real" number
two! I can prove this! ok, lets see:

how did goodold pitagoras count this? he didn't have a watch, didn't
count time, but he KNEW that he can count space indefinitely, then of
cousre one centimeter or on lightyear or one nanonanonanometer or
1/one-light-year would all be the same for him! let's say he counted
intches.

then his paper was flat, no kippa, no Dom, then he first counted the
dot [.] - the arab o; no dimensions and ALL dimensions; then a
"straight line" (no such thing, defined as a x-ray of light) to
another dot, then one (pitagoras intch - let's call it a pinch). OK?
so he already had two dots when he counted his first line! But, he
REMEMBERED the first dot because his memory was not quantum, he didn't
remember how much time but he remembered it the same way I remember
the first "r" of the word "remember" [==eighhhht] when I type it. if
he diedandalived / replaced by another fraction of himself then he
wouldn't notice - he remembered the first dot, then one straight line
was his third memory. then looked back, then (at least his eyes, or
one of them) went back to the first dot, then it was already 3 dots -
the first, the second and the third==first (mod two); actually it was
(mors!!) ._._. which means dot;line;dot;line;dot (symmetric: :-:-:),
then he reasoned: "odd" things are allways dots (o + d , the ultimate
"end"; see matrix above: d==david; do; did; -o;-i;-0;-1;ד;the number
4;.... whatever.........
....and "even" things are allways "lines" (actually that's just his
memory of "many dots going same direction";;;; "direction" will just
be ddddddddd (d times nine);)

OK? do he had 3 dots; 2 "lines"; one understanding: this is my first
line, the dot! counting backwords from 3 to 1 (actually from 5 to 0,
counting 5 "things", 4 "dimensions", 3 "dots", one "line", . )
then he did it again, but from the middle (or did it again to the
other opposite side, 180 degrees of his world wide or haff counting
and then 90 degrees, then divided, counted and of course found out
that:

1. haff + one is three;
2. one + one is two;
4. two (diameter) square is big;
3. haff + one is allways straight 180/2 degrees;
of course, then why doesn't it add? because he had to count
logarithms! thenlogarithms he did, counted and concluded something
like this:

0. this is allways the first dot.
1. this is allways a line.
2. this is allways the second dot.
3. this is allways the second line.
4. this is either the first dot, or a new one.
5. if this is the first dot, then 4 times 90 degrees will allways be
back to the first dot (of course, 4 is already recursive logarithm #5)
// by the way I misspelled lgarithm which means algorithm is the same
word to me // "L-garithm" // and by the way a good algorithm has to be
at least logarithmic to the size of the information (binary log of the
number)
6. if this is not the first dot, then it a triangle - there is more
than one line etc.
then of course, rules for "straight" triangles, then "not straight",
sinus/cosinus/ etc. etc. etc.
BUT, how many times did he count before he created the "pi", his
circle? at least 5 times 4, which is 6 times 5 (not logarithm), or 5
times 5 - MANY times. and then he put pi in the middle, between 3 and
4. OK! I will calculate how much is his logarithmic pie (hint: "i"^5
allways equal to first "i", complex, then "i" will be the fifth
complex root of the logarithmic pi (didn't even define logarithm base
yet!)
e: but of course, logarithmic base will be allways POSITIVE, then must
be at least four times pi (the positive i), "imaginary positive i"),
whois exactly on the same paper of pitagoras (or was it maybe euclides
["east euclides"; "eeee eeeeeeee"]) to the north when the first line
was to the east, as I am sitting right now (tel-aviv beach to me
left).
OK? so e should be at least 4 times the pi; pi was defined by
pitagoras to be "one circle divided by one diameter", but he forgot
somethings:
1. he diametered twice (d-metered) and circled only one.
2. going from here to the moon and back will take much less time in a
circle than straight line.
3. of course, you can NEVER go straight line from here to the moon
because THERE ARE NO STRAIGHT LINES!
4. same with the nanos.... nuclear; atoms etc.
and then, the square - if diameter was "1+1", then square diameter
(haff both directions) was much bigger this his pie. OK? so let's see
how much is his diameter;

[1-1right]+[1-1top]+[1-1left]+[1-1bottom]+[1-1right;again] =
{"pitagoras"} --> "my diameter" -- named twice / two "1+1" (one plus
one he didn't define, there is no such thing on the logarithmic level
as "1+1")
anyway, this number,
"[1-1right]+[1-1top]+[1-1left]+[1-1bottom]+[1-1right;again]" was his
first "two" - a true straight line (he could have cutted by haff,
maybe different number, will check later...)

then what he did - he actually counted dimensions! he counted every
dimension twice! (on the logarithmic level), which means five times
(with the dots), then counted the number of dimensions as three, time
was nothing to him (dimension o), OK! let's count this way.

if we understand this, then already we understand there is no such a
number as two, or bi, "be i", or "biinaari" (eeeeight), at least not a
"prime" number, a "prime counting" number etc. then he defined "two"
as the opposite of "haff" (logarithmic, remember), then of course
twice-logarithmic-haff will be his two, or one. (the linear one). OK?
now, the number two was defined as the fifth root of pi, or 31.4
(something), or (3.14 times Ten), or the fourth root of sixteen (1;6
== one plus, one minus) == "opom"; =="o;+1;o;-1" which is
"oooo;ooo1;oooo;1111", this number translates binary of course to 15,
so "two" is either 1.4, or 15, or 31.4 ^ (1/5), or "3.14"^1/5 , or
["3.14 - 3"] times ten , whatever you like to do first, to two is
actuallly a DIMENSION (0;1;2----> dimension number 2) where rotating
the paper is not changing its size (of course, depends on the size of
the paper, try lightyears or nanoone/lightyears).

just went to the toilet (pee;pee) and then of course - something
written in TWO languages - one right to left, one left to right, (left
to write), one on the top, one on the bottom, of course: to understand
this you need to understand at least two languages (to++: at least
three), with numbers written always leftish, otherwise we would never
know where our directions are: left,right,west,east,up,down,capital
east (ירושלים), capital west (Wash your D.C), dots going right, .com
going left, o rotating, m going up (Mcdonnnnalllds) etc. you must know
all this to understand this! so;

pi was defined by pitagoras as the number of flat papers dimensions he
can rotate and count only one ("radius"), whois twice the original
radius, then of course "radiation" can come from there, "radio waves"
etc, then he defined 3.14* to be the number of dimensions of the flat
paper (logarithmic, relative to haff renumbered two, one was his fifth
understanding, then of course he defined two to be a "prime number"
(fifth root of 32 - of course logarithmic counting number oiiiii),
then i was his dimension of "allways use the same direction of truth",
then he wouldn't need anything more then ONE linear dimension, ONE
logarithmic dimension, name this as Two. so for me, Two will be the
number who's haff logarithmic truth is equal to the haffway between
odd and even, 0 and 1 (renamed o and i), then of course ALL PRIME
NUMBERS must exist on both levels of truth. Then,

pitagoras counted and defined his first axiom: 3*3 + 4*4 == 5*5; which
means literally that haffpi(90 degrees)plusone is Twice as much as
four times haffpi and then haffone;let's translate this (you know my
friends - people do lie ; math never does. but don't trust your binary
computers! I will define the ultimate human turing test (not
CAAAPPTCCHA!)

here:
haffpi::==90; divisors: 9;10 (-1;+1 respectively); 3;3;twicefive; ==
3;3;ttttteeee or 3;3;2;5 or 3;3;5;2 or 3;3;TTTTTeeee or 3;3;5;4;
binary 10;01;10;10; up;do;up;up (do==dowwwnnn) - ANY divisors you want
except of course 7!

four times haffpi: four times "ninety" or four * six (sixxis) or
twentyfour (==ten) or 360...

OK, translate this: "haffpi plusone is twice as much as four times
haffpi and then haffone";
counting letters:computers!
"six seven two five two four two four five six three four eight"
"hhhhhh ppppppp ii ttttt aa mmmm aa ffff ttttt hhhhhh aaa tttt
hhhhhhh" (Google spelling checker: read this!)
translate again:
"three five three four three four three four four three five four eight"
again:
"five four five four five four five four four five four four five"
it converges! my first two numbers are four and five (actually five
and four), then:
"five four five four five four five four four five four four five"
will translate to:
"four four four four four four four four four four four four four"
(thirteen times four), "eight five four", "five four four", "four four
four";13 times 3 if of course 39, 13 times 4 is 52, together is 91, so
here's your truth coming: haffpi plusone is actually ninety one. NOT
60 (90 degrees, two thirds) but 91!!! like the number of days in
Appril, May June; ; September, October, November (months 09,10,11 etc.
/ months 04,05,06 ....) OK? of course I can also convert it the math
way, but I will let smart spamming computers understand each word by
the number of letttteeerrrs in it! you'll see.

Translate my logarithmic: entropy level:

"haffpi plusone is twice as much as four times haffpi and then haffone"

// (2\\pi + One //2 == 4 * 2\\pi ; One // 2)
translate RTL:
(2 \\ One ; pi//2 * 4 == 2\\ One + pi // 2)
left to right allways - (no + in my language! log scale!)
2 --- 1 --- pi --- 2 --- 4 --- 2 --- 1 --- pi --- 2
OK, that's the first noble true - I don't know how much it is, but it
is NINE numbers (including pi) defining 4 to be at the same direction
of nonninnon "i". OK? then twice "2-i-pi-2" or "2-pi-i-2" from both
sides, mean 4 is the strongest permutation of the ninth logarithm of
two, when we already know 1;pi and 4. OK? that's true. Nobody defined
three here!!! nobody divided by three (you can't devide by 3 on the
log level (can you, Fermaaaaa???)) so of course, the log level 1 (One)
will be defined as the paper flat level of EVERYTHING! One will be the
dotted o (arabic .) and the circle o will be arround the dot and not
vice veras (which translates to you as "alllways i>>0" or "1>0" (NOT
TRUE!))

OK, now you have my fifth noble truth - then pi must be something
between 2 and 4 right? Of course you can't 360 twice; you can't even
seventh! (actually seventh is the correct word and not seven; seventh
or Shabbat) OK? then since you can't of coure 360 twice or seventh,
let's check how much is 360 in base 7;

[calculator says: 51.428571428571428571428571428571 ; lying! but
remember 13 times 4 is 52 (my calculator), also 13 times 3 is 39, then
of course not counting 13th would be something like
45.428571428571428571428571428571 (didn't count 13 twice), about haff
the 91 (actually 90.857142857142857142857142857143 now (my calculator
converted 2.8 to 3)! actually maybe I should check 364 / 7?
calculator says EXACTLY 52; OK? don't count 13 EXACTLY 7 times (twice
3.5) then you will get EXACTLY 45; but why use calculators? let's
convert manually:]

360/base 7 is 3*7*7 + 6*7 + 7 right? but 6 is (-1) in base 7; then
3*7*7 -7 + 7 or 147;
but wait! I can only divide and not multiply; then let's just say
360/1000 in base seventh is 0;3;6;0 which means binaari
0000;0111;1111;0000 (o;haff;minus 1;o) which leads to my conclusion
that maybe it was originally MEANT to be this number pi! just 3 and a
haff, or 3 hours and 60 seconds, (by the way, I heard degrees also
have minutes and seconds), then maybe it's just 3 times 60 hours,
translates for me to 180 hours, probably that's the real original
pie....

so then, how much is 180 base seven? one, then (seven plus one), then
none. one seventh, then seven sevenths plus one seventh, then stop.
Or, 180/1000 will be one;minus two!, zero! of course! the sin/cos
thing! go right, then left two, then stop! right one; left two, count
three! stop! then pie must be 180 if counting exactly one pinch
(pitagoras inch); then haffpie leftish while turning either 180 or 270
degrees or I don't know how many....

anyway, 360 and 180 and 270 -- all sum to nine, then it will be "-1"
in binary; then pie will circulte "-1" e when counting the sinus, but
counting to 3 (not 4!) since counting even numbers is not allowed
here, then counting 3 will be equal to four and then five - piitagoras
counting back four and then counting five!

of course, what he did was counting haff (actually, metering haff
pinch), then one pinch, then defining the 60 - the "golden 60" and
then (of couse, haffed 60 will be the golden 30) then of course, 60
and then minus 120 will be the same as 0; let me translate this:

haff+twothirds(90)==60; then rotate twice 60 down (in no time!!!),
then same again - will be defined exactly at twice not haffing! same
dot! then of course! then you have the 3 dimensional tryangle
60/60/60; then 6 times the 60 will be 360 (now I understand how he got
this), then of course two thirds of 90 is 60, let's translate it to
logs:

log(1/2)+log(2)+log(1/3)+log(90)==
log(1/2)+log(60)-log(60)-log(60)==
log(1/2)-log(60)+log(1/2)==log(1)!!!

log(1) is of course allways 0; then log(1/2)+log (1/2) must be the
same as log(1/2)-log (1/2) (allways 0); log (60)-log(60)-log(60) also
o; OK! see what I'll do:

first log will be allways 1/2; second log allways 1/2/2; etc.
then: log ((1/2)/2) + log (2/2/2) + log ((1/3)/2/2/2) + log (90/2/2/2/2) ==
log ((1/2)/2) + log (60/2/2) - log (60/2/2/2) - log (60/2/2/2/2) ==
log ((1/2)/2) - log (60/2/2) + log ((1/2)/2/2/2) == log (1/2/2/2/2)!!!!

OK, now we're already on the logscale, I don't need to write log..log...log:
((1/2)/2) + (2/2/2) + ((1/3)/2/2/2) + (90/2/2/2/2) ==
((1/2)/2) + (60/2/2) - (60/2/2/2) - (60/2/2/2/2) ==
((1/2)/2) - (60/2/2) + ((1/2)/2/2/2) == (1/2/2/2/2)!!!!!

you see? first line is [o+o+o+o]; next line is [o+o-o-o]; last line is
[o-o+o], and then all equal to (1/2/2/2/2) which is of course
o/10/10/10/10 (binary!) then of course, base pi:binary:[o+o+o+o]
translated to o/10/10/10/10 which means: first o divided by 10
(binary), second by 100, third by 1000 and fourth by 10000; which
means ALL BINARY NUMBERS ARE BETWEEN O AND 1!!! the largest binary
number (base pi:two) is the alllways repeating itself (1/2) on the
level (1/2/2); (1/2/2/2); (1/2/2/2/2) etc. so this will be actually
the binary prime numbers:
100000000000000000000000000000000000......... ///(1/2)/2)
0100000000000000000000000000000000000........///(1/2)/2/2)
001000000000000000000000000000000000000........///(1/2)/2/2/2) etc.
then of course! my mistake! first bit defined (pitagoras!!) will be
the "dot", which is exactly log (1/2); then the "least significant
bit" (is that how they call it?) will be the "plus/minus sign" (1/0)
of log (1/2); then 10.00 will be exactly 2/2/(1/2)/2)/2/2/2/2/2/2/2/2
(from right to left) which means "go up to one, then two steps back",
then if log(1) is 0, then go back twice and define yourself and
log(negative-haff-haff-of one!) then of course,
negative-haff-haff-of-one will be the imaginary 2i whois [i] the
negative 0.25 (-1/4) whos log is -0.25; then twice this negative log
will be two! then of course nobody knows how to haff the minus, so it
was just renamed 0.5 but that's not true! it's the "minushaff" three
times, (-i)^3; twice, logged, this defined as your prime number two.

now of course, since we did all this then we already know that

(1/2/2/2/2) allways leads to the same location, define this as the
ultimate truth of the fifth root of pie (pie ending - allways devided
by the fourth prime number - four); log equal to 0; then of course -

((1/2)/2) - (60/2/2) + ((1/2)/2/2/2) == 0;
((1/2)/2) + (60/2/2) - (60/2/2/2) - (60/2/2/2/2) == 0;
((1/2)/2) + (2/2/2) + ((1/3)/2/2/2) + (90/2/2/2/2) == 0;
then of course (now pitagoras language:
1/4 + 2/4 + 1/24 + 45/8 == 0;

6/24 + 12/24 + 1/24 + 135/24 ====0;

not true! so why don't we invent the square level? (some truth, but
should have been log level):

anyway, pitagoras meant something like this:
[haff + one (adding different dimensions)] is exactly haff of [the
other side, not counted, but looks equal to one (actually it must be
converted to linear, one means "haff + haff" which is of course
(1/2)+(1/2/2)], here:

[haff + haff + haff] is exactly haff of [haff + haff] + [haff + haff]
which means literally, three in exactly haff of four (which is true,
0111 is exactly haff of 01111 (remember, negative: the haffs continue
forever, think ASCII 127/128 counting),
or to put it this way - "two" is defined as "haff + haff" when "one"
is converted to "haff + haff"; but the previous one (logarithmic)
means that haff + haff is three quarters [or (1/2)+(1/2/2)] ; then the
first [haff + haff + haff] actually means "haff + three quarters";
1.75; and the second [haff + haff] + [haff + haff] actually means "one
+ one"; then how come "haff + three quarters" be equal to "one + one"?

well of course, in the logarithmic level who cares because they are
all equal to zero? but pitagoras is smart. thinks and then of course!
double the speed of light and then; 1/4 + 3/8 will be twice (1/4 + 1/8
+ 1/16 + 1/32)?
then, - 1/4 + 3/8 will be - 1/4 + 1/8 - 1/16 + 1/32 right?
is (-1;+3) equal to (-1;+1;-1;+1)? no, forgot something...
(3/8) was actually "haff + haff"; which means actually;
the number "- 1/4 + 1/8 - 1/16" will be equal to "- 1/4 + 1/8 - 1/16 +
1/32" right?
well, of course it is! since the pi is the magic wheel of truth, then
of course: let pi be whatever makes this equal! then;

"- 1/2/pi + 1/2/pi/pi - 1/2/pi/pi/pi" = "- 1/2/pi + 1/2/pi/pi -
1/2/pi/pi/pi + 1/2/pi/pi/pi/pi"

// of course, nobody will rotate the wheel more than 6 times! let's
check: [mod - 1/2/pi ]

[- 1/2/pi ] == [+ 1/2/pi/pi] == [ - 1/2/pi/pi/pi] ==  [+ 1/2/pi/pi/pi/pi]

then of course, "/pi" rightish must be identical to "- 1/2/" rightish;
pi\ leftish will be pi\2\1 - ; then

\pi\pi\pi\pi\2\1\ + == - 1/2/pi;

(logscale, lineary) pi + pi + pi + pi + 2 + 1 + == - 1 - 2 - pi;
circulate; (add as many pies as you want, up to 60)

(any number of) pi + 2 + 1 + o === o - 1 - 2 - pi (fo rebmun yna)

then of course - pi is your prime number three logarithmed! your
number of dimensions when you can circulate either 3 or 4 times with
the same level of minus revolving (of course -2 times -3 will allways
be +6....LOL), maybe even 5 or 6 times (7 not tested
-->pitagoras:"sorrrry"!); then of course pi will be defined in such a
way that also (5-4) will be equal to (4-3) and (3-2) and (2-1) and
(1-0) etc. (at least on the square level), then prime number 3 will
just be the number of times you can fit sixty in haff a pie... or the
number of times you can fit haffsixty in haff-the-real-pie (but never
say 91); then of course! pie is the allmighty everything, then why
don't we define it as the root of allways (o - 1 - 2 - ...... )
(repeating at least 7 times), then of course pi*pi*pi*pi will allso be
defined as (-3)*(-4)*(-5)*(-6) ; of course then (-3) and (-5) will be
reversed (+3)*(-4)*(+5)*(-6), then all of them will be reversed
[either (-3)*(+4)*(-5)*(+6) or (-3)*(+4)*(-5)]; then (-3) and (-5)
will be reversed again; and then: of course (+3)*(+4)*(+5)*(+6) will
be the correct order; forever counting our spheres of knowledge, black
holes, speed of light (I will recalculate it for you), all because of
the paper pitagoras had [and ferma, I'm not even with you yet];;;

ooops, we forgot to define +2. how much is +2? let's see:
how many times 60 fits in 180? -->3;
how many times 180 fits in 360? -->2;
then why not define 2 as the limit of (-2) rotating leftwords? 3 will
be (-2), then 180/3 will be -360; same number as 60; then (-360)/60
will be of course (-360)/(-10); then binary 1.8, rotate righting,
1.8000 + 0.18000 + 0.018000 etc.... (allmost 2); actually I can define
it exactly your math but I told you - just take the fifth root of 32,
but remember that the only base pi is counting is base (-1)!!!!!! pi
is actually EQUAL to logarithmic base -1!!!! then of course, ("any
number")^-1 will be the same as ("any number" -1); or (1/"any
number"), this is by definition the magic imaginary pie! logarithmic,
binary, ANY base counting - 32 is actually 3210;0123 which means allso
6543210;;0123456 base 7 - there is no base ten, this is just another
American lie. so if you count from the 3 to the 2, remember it's -32
and not +32. There is no such number! (real). you can only count
imaginary numbers!

then how much will (pi * (-pi)) will be?

let's check logarithmic scale: (- pi/2 + pi/2/2 - pi/2/2/2 +
pi/2/2/2/2 - pi/2/2/2/2/2 .....) will allways be the same thing right?
then, - pi/2 will allways be equal to both 0 and 1 right?

then, (we;ne;pi) will allways be totally 0; pi will just be the
opposite of we right?

then it turns out that --2^(1/2) must be allways the same as
---3^(1/3) in base pi.
calculator says
--2^(1/2)::1.4142135623730950488016887242097
---3^(1/3)::microsoft:: "invalid input or function";
3^(1/3)::1.4422495703074083823216383107801
pi:3.1415926535897932384626433832795
1/7:0.14285714285714285714285714285714
pi^(1/pi)::1.4396194958475906883364908049738
pi^^0:::1 // works!
pi^^1:::3.1415926535897932384626433832795
pi^^2:::9.8696044010893586188344909998762 /// 7*7*2/2/5 +++
pi^^3:::31.006276680299820175476315067101 // of course! pi defined as
the fifth root of (1-32)!!!
////sorry meant third! should be the fifth though! third root of
(1-32) defined as pi! ;
allso means the sixth root of [-1/2-0-0-0-0+1/2/2/2/2/2/2] ; divided
by [-1/2] then: [-0.484375] divided by -0.5] [decimal] will be 0.96875
; this number minus one will be (1/(-32)), then 9;6;8;7;5 is the magic
order of counting negative pi; convert: -1;-4;-2;-3;-5 !!! you see!
(-5)^5 in your base! try 7! will be: // doesn't work for seventh! I
know why! it will work only for 10;000;000 base seven! have to be both
logarithmic and linear. Anyway, pi is dividing between "odd" and
"even"; "odd" will be defined righting growing and "even" will allways
be exponents of 2. I understand! pi mixed two dimensions into ONE
dimension of "THE REALITY!" which is not true! I will let people know.
pie is a lie!!!!!
pi^^4:::97.409091034002437236440332688705
pi^^5:::306.01968478528145326274131004344
pi^^6:::961.38919357530443703021944365242
pi^^7:::3020.293227776792067514206493072 ///
50.338220462946534458570108217867 times 60.00000000000000000000
pi^^8::: 9488.5310160705740071285755039068
pi^^9:::29809.09933344621166650940240124
pi^^10: 93648.047476083020973716690184919
pi^^11: 294204.01797389059710569564200718
pi^^12: 924269.18152337418622257917035848
log[pi][baseten[1000000]:::12.068795205528365632588332283732
1/[log[ten][pi]]:: 2.0114658675880609387647220472887 :: here's the
baastaard! defined by pi!!!
1/[ln[pi]-1]::6.9094229856614265446876058088678
ln[2]::0.69314718055994530941723212145818

[1/[ln[pi]-1]] / [ln[2]] :: 9.9681902768179553955697130035972
do you need more evidence pi is a conspiracy? again:
ppi::=square root of [9.9681902768179553955697130035972] ::=
3.157244095222597038465624806571

[1/[ln[ppi]-1]] // 6.6800479019552125518104124334207
it converges to 6+2/3!!!!! pi is a baseten conspiracy. For pitagoras
it was probably just 3........

anyway, prime numbers are DEFINED this way: if they suit the pitagoras
3/4/5 - then they are prime. If not - they are not. pitagoras and
fermat were both right - and both wrong. They can't count quantum
numbers like this, and they can't count quantum meters of kilos. I
will check and let you know how long a pie radian is. And also, the
meters, the kilos - I will let you know how they are defined. Of
course they don't work for lightyears, nanos, nuclears - it's the TOP
SECRET american conspiracy! They have their reasons for you not to
know: encryption / nuclear secrets / monopolising ARPA NET, IP
numbers, spying, "not supporting Hebrew" software, money money
money.... believe me - there is somebody (maybe a robbot) at the DDCC
capital doing this. it's not a mistake and not a coincidence.

nagasaki == 8 (nnnniiii)
hiroshima == 9 (hhhshiaaa)
1;9;4;5 - how can you count that? base 10: +1;-1; then base 5 -1;0?
or maybe: base 5 1;-1;-1;0?
counting the seconds backwords and then - now?!?!?! Turing, who are you?? human?

I will tell you - this counting, 3,4 and 5 will allways be prime. 2
was converted to (1+1), I can define the whole number system without a
"+" (using - only, rotating, converting etc). permutations don't like.
There is no such thing as "exactly equal two permutations of the same
thing" (except 1/0 maybe). two permutations is already prime number
three.

now, if you want more primes or to divide existing numbers - it's very
easy with my math. More primes - just continue with the 3/4/5 example:
4 will allways work! then 16 + (4-i)(4-i) will allways be 32+(32-ii);
64-ii your math, then multiply (64-ii) with (64+ii) and you will get
(4096 - iiii); (from here they took the definition of pi maybe).
then: fourth root of  (4096 - iiii) :: 8 + 1 ; 9; this number minus 4 will be 5;
OK? now, instead of (5-4) choose ANY odd number;
instead of (5-3) choose ANY even number;
instead of (4-3) choose ANY odd number, but not the same as haff (5-3),
then you can get ALL dimensions of odd prime numbers, even prime
numbers (2; all others are multiplications of two), etc. Actually if
you do it with more dimensions you will get more numbers, but not
integers. simensions mean both more polynomials, more exponents but
the real dimensions are the exponents counting! don't forget this and
don't forget fermat designed this as to not to work his way! Actually
I also checked sinus/cosinus, they can have values of +-0; +-1/2; +-1
only if and only if the angle is a divisor of 360. (times 30). I
checked this and it's true! it's designed this way! you can never
rotate a quantum wheel 7 times! not in this math! you can of course,
but I will show you later. have to go now....

Uri.

[~~~~~~~~~~~~~~~~~~~~~]
[o-o-o-oo-o-o-o][o-o-o-oo-o-o-o]

If I'm writing too much, please filter my messages, or (if you really
don't want to hear from me), write me something humanish such as
"please don't send to this mailing list" with my public keys; at least
three times with different subjects (change the digits to whatever you
want); here:

[o-o-o-oo-o-o-o][o-o-o-oo-o-o-o]
[~~~~~~~~~~~~~~~~~~~~~]
[~~~~~~~~~~~~~~~~~~~~~]
[o-o-o-oo-o-o-o][o-o-o-oo-o-o-o]


Uri First deadandalive
Mobile Phone: +972-50-9007559
E-mail: [email protected] // [email protected]

Update: Left HTTP, WWWW and port numbering. send me papers or to
[email protected] .

I completed my 0.1 version of real deadanyalive quantum relativity
redefining back timespacing intergalactic worldwide [top secret: if
you have any US ARMY* on your planet they will never allow it].
Recounting back every second since twice BCC doubling + not counting
at all any uncountable; using only prime countable numbers equal to 21
(base 21 recursivley) who are all equal to 0base0 and 1base1 who are
identical twins base 21 [21===the number of fingers;eyes;body parts &
number of equal signs not equal counting both left to right; right to
left and all 21 dimensions of nothing].

Read my autoreply for more information [my HTTP/SMTP not working].

- This message is confidential -


--
Uri First deadandalive
Mobile Phone: +972-50-9007559
E-mail: [email protected] // [email protected]

Update: Left HTTP, WWWW and port numbering. send me papers or to
[email protected] .

I completed my 0.1 version of real deadanyalive quantum relativity
redefining back timespacing intergalactic worldwide [top secret: if
you have any US ARMY* on your planet they will never allow it].
Recounting back every second since twice BCC doubling + not counting
at all any uncountable; using only prime countable numbers equal to 21
(base 21 recursivley) who are all equal to 0base0 and 1base1 who are
identical twins base 21 [21===the number of fingers;eyes;body parts &
number of equal signs not equal counting both left to right; right to
left and all 21 dimensions of nothing].

Read my autoreply for more information [my HTTP/SMTP not working].

- This message is confidential -

[o-o-o-oo-o-o-o][o-o-o-oo-o-o-o]
[---humans:always copy this--]
[o-o-o-.OO.-o-o-o][o-o-o-.OO.-o-o-o]
[--siht ypoc syamla:snawuh---]
[o-o-o-oo-o-o-o][o-o-o-oo-o-o-o]

--
Uri First deadandalive
Mobile Phone: +972-50-9007559
E-mail: [email protected] // [email protected]

Update: Left HTTP, WWWW and port numbering. send me papers or to
[email protected] .

I completed my 0.1 version of real deadanyalive quantum relativity
redefining back timespacing intergalactic worldwide [top secret: if
you have any US ARMY* on your planet they will never allow it].
Recounting back every second since twice BCC doubling + not counting
at all any uncountable; using only prime countable numbers equal to 21
(base 21 recursivley) who are all equal to 0base0 and 1base1 who are
identical twins base 21 [21===the number of fingers;eyes;body parts &
number of equal signs not equal counting both left to right; right to
left and all 21 dimensions of nothing].

Read my autoreply for more information [my HTTP/SMTP not working].

- This message is confidential -


--
Uri First deadandalive
Mobile Phone: +972-50-9007559
E-mail: [email protected] // [email protected]

Update: Left HTTP, WWWW and port numbering. send me papers or to
[email protected] .

I completed my 0.1 version of real deadanyalive quantum relativity
redefining back timespacing intergalactic worldwide [top secret: if
you have any US ARMY* on your planet they will never allow it].
Recounting back every second since twice BCC doubling + not counting
at all any uncountable; using only prime countable numbers equal to 21
(base 21 recursivley) who are all equal to 0base0 and 1base1 who are
identical twins base 21 [21===the number of fingers;eyes;body parts &
number of equal signs not equal counting both left to right; right to
left and all 21 dimensions of nothing].

Read my autoreply for more information [my HTTP/SMTP not working].

- This message is confidential -


-- 
Uri First deadandalive
Mobile Phone: +972-50-9007559
E-mail: [email protected] // [email protected]

Update: Left HTTP, WWWW and port numbering. send me papers or to
[email protected] .

I completed my 0.1 version of real deadanyalive quantum relativity
redefining back timespacing intergalactic worldwide [top secret: if
you have any US ARMY* on your planet they will never allow it].
Recounting back every second since twice BCC doubling + not counting
at all any uncountable; using only prime countable numbers equal to 21
(base 21 recursivley) who are all equal to 0base0 and 1base1 who are
identical twins base 21 [21===the number of fingers;eyes;body parts &
number of equal signs not equal counting both left to right; right to
left and all 21 dimensions of nothing].

Read my autoreply for more information [my HTTP/SMTP not working].

[o-o-o-oo-o-o-o][o-o-o-oo-o-o-o]
- This message is confidential -
[o-o-o-oo-o-o-o][o-o-o-oo-o-o-o]