Re: time difference

sorry, html highlighting did not work.

Here again:

#!/bin/bash

while IFS=';' read Num Date_1 Status_1 Date_2 Status_2
do

DATE1=$(date '+%s' -d "$Date_1")
DATE2=$(date '+%s' -d "$Date_2")

let "DIFF = ($DATE2-$DATE1)/86400"
echo -e "$Num\t;$DIFF;\t$Date_1;\t$Status_1;\t$Date_2;\t$Status_2"
done < your_input_file

---end of script






On 11/12/12 18:40, MOKRANI Rachid wrote:
>   
> Hi,
>
> I have a file like below (with more lines) and I want to compare the elapse time beetwen two date and insert the result in a new colum.
>   
> My file :
> Num ;        Date_1       ; Status_1 ; 	Date_2		; Status_2
> 14  ; 2012-10-11 18:09:33 ; CONFIRME ; 2012-10-12 12:33:02 	; REJETEE	
> 15  ; 2012-10-11 18:09:56 ; CONFIRME ; 2012-10-12 18:24:29 	; REJETEE 	
> ...
> ...
>
>
> I would like to have in the result.
>
> Num ; Elapse_time_in_days ;        Date_1       ; Status_1 ; 	Date_2		; Status_2
> 14  ;         0           ; 2012-10-11 18:09:33 ; CONFIRME ; 2012-10-12 12:33:02 	; REJETEE  ;	
> 15  ;        32           ; 2012-10-11 18:09:56 ; CONFIRME ; 2012-11-12 18:24:29 	; REJETEE  ;	
> ...
> ...
>
>
> I can calculate the différence time like below but I don't know how to insert the result in a new colum with sed may be.
>
> date +%s -d "2012-10-11 18:09:33"
> 1349971773
> date +%s -d "2012-10-12 12:33:02"
> 1350037982
> expr \( 1349971773 - 1350037982 \) / 86400
> 0
>
>
> date +%s -d "2012-10-11 18:09:56 "
> 1349971796
> date +%s -d "2012-11-12 18:24:29 "
> 1352741069
> expr \( 1352741069 - 1349971796 \) / 86400
> 32
>
>
> Many thanks in advance for any help/idea.
> Regards.
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