Re: right justify each line?

I double-checked my sent folder, and a copy sent to myself. Actually, I 
did post sensibly, but yahoo did not transmit sensibly. Unfortunately, 
yahoo stripped out leading blanks from the lines, so yes it ended up 
input.x = output.x :( So so thanks for asking.

Please look at the following, and imagine that the colons are not there, 
and that's how I posted. In this case, each line has five characters, 
but it could be a different number of characters.

$ cat input.x
:99   :
:   99:
: 9   :
: 9 9 :
:99999:

$ cat output.x
:   99:
:   99:
:    9:
:  9 9:
:99999:

In case yahoo mangles the above, here is another way to display it, 
where you would please imagine that each '-' is a blank.

$ cat input.x
99---
---99
-9---
-9-9-
99999

$ cat output.x
---99
---99
----9
--9-9
99999

Thanks,
Daniel

On 11/14/2015 9:36 AM, Rakesh Sharma [email protected] [sed-users] 
wrote:
> Your input.x = output.x and also what do you mean each line in input.x has the same length? look at the line 99999.
>
> You need to post sensibly first.
>
>
> ________________________________
> From: [email protected] <[email protected]> on behalf of Daniel Goldman [email protected] [sed-users] <[email protected]>
> Sent: Saturday, November 14, 2015 9:25 AM
> To: [email protected]
> Subject: right justify each line?
>
>
>
> Hi,
>
> Assume each line in input.x has the same length.
>
> $ cat input.x
> 99
> 99
> 9
> 9 9
> 99999
>
> I want to right justify each line, so output.x would be:
>
> $ cat output.x
> 99
> 99
> 9
> 9 9
> 99999
>
> What is simplest way to convert input.x to output.x?
>
> I tried the following, but does not work, because of greedy evaluation,
> \2 always encompasses the entire line.
>
> $ sed "s/^\(.*\)\( *\)$/\2\1/" input.x
>
> Thanks,
> Daniel
>
>
>
>
> [Non-text portions of this message have been removed]
>
>
>
> ------------------------------------
> Posted by: Rakesh Sharma <[email protected]>
> ------------------------------------
>