RE: compare files

 Since this is a "sed" editor forum, a sed-based solution is presented:
 

 Note that you need to place a dummy line of all stars ******
 as the last line of the 2015.txt file in order to distinguish the
 ending of 2015.txt & start of 2016.txt.
 

 Assuming the GNU "sed" being used, for two main reasons, enough 
 memory for hold space & [^\n] regular expression for a nonnewline to
 be matched.
 

 Ordering of arguments is: 1st arg = 2015.txt 2nd arg = 2016.txt
 

 sed -e '
 

 1{
    # read in the 2015.txt file
    :f2015
    $!N
    /\n\*\**$/!bf2015
    s///;h;d
    # now the 2015.txt file is in the hold space
 }
 

 G
 

 # same
 /^\([^\n]*\)\n\(.*\n\)\1\n/{
    s/^\([^\n]*\)\n\(.*\n\)\1\n/\2/;h;$bend;d
 }
 /^\([^\n]*\)\n.*\n\1$/{
    s/^\([^\n]*\)\n\(.*\)\n\1$/\2/;h;$bend;d
 }
 /^\([^\n]*\)\n\1\n/{
    s/^\([^\n]*\)\n\1\n//;h;$bend;d
 }
 /^\([^\n]*\)\n\1$/{
    s/^\([^\n]*\)\n\1$//;h;$bend;d
 }
 

 # modified
 /^\("[1-9][0-9]*"\);[^\n]*\n.*\n\1;/{
    s/^\(\("[1-9][0-9]*"\);[^\n]*\n.*\n\)\2;[^\n]*\n/\1/;tmodified
    s/^\(\("[1-9][0-9]*"\);[^\n]*\n.*\n\)\2;[^\n]*$/\1/
    :modified
    h;s/\n.*//;s/./&/w /tmp/modify_from_2015.log
    g;s/^[^\n]*\n//;h;$bend;d
 }
 /^\("[1-9][0-9]*"\);[^\n]*\n\1;/{
    s/^\(\("[1-9][0-9]*"\);[^\n]*\n\)\2;[^\n]*\n/\1/;tmodified
    s/^\(\("[1-9][0-9]*"\);[^\n]*\n\)\2;[^\n]*$/\1/;bmodified
 }
 

 # new line
 s/\n.*//;s/./&/w /tmp/new_in_2016.log
 $!d
 

 :end
 g
 '  2015.txt    2016.txt > /tmp/remove_from_2015.log
 

 HTH
 

 -Rakesh

 



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