Re: Semantic parses even if incorrect operator used

On 02/24/2015 04:12 PM, rjd wrote:
> Whether I create a pointer to a user defined object or instantiate a user
> defined object, I can interchangeably use the -> or . operators to access
> members/methods.
>
> === EXAMPLE ===
>
> #include <iostream>
>
> struct MyStruct
> {
>    MyStruct( void ) { }
>    ~MyStruct( void ) { }
>
>    int data;
>    int getData( void ) const { return data; }
> };
>
> int main( void )
> {
>    MyStruct* ms = new MyStruct();
>
>    ms. // works
>
>    return 0;
> }
>
> === END EXAMPLE ===

Yes, we don't bother checking the type of punctuation.  I figure the 
compiler should be good at that, and adding those checks in completion 
would just slow it down.

I suppose it would be cool if you typed "." and it converted it to "->" 
automatically if it could figure it out.   Probably wouldn't be too hard 
to figure out.

Eric

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