Re: Train running cost

El Dimecres 02 Novembre 2005 16:11, Booth Antony va escriure:
> Sounds like a good idea, however, maybe you should put some brackets in.
> Eg.
>
> Train runing cost = ((MC + LC) * NL) + (WC * NW) + (AR * TS)^2

This equation is ok for steam locomotives, but for electric/diesel locomotives 
the equation should be:

Train runing cost = MC + (LC * NL) + (WC * NW) + (AR * TS)^2

And I don't known if aerodynamic resistence is (AR * TS)^2 or AR * (TS^2), but 
I think that (AR * TS)^2 is wrong.

> I think that is the spirit of the equation you were aiming for....
>
> -----Original Message-----
> From: Jaume Sabater [mailto:[email protected]]
> Sent: 02 November 2005 11:37
> To: [email protected]
> Subject: [ttdpatch] Train running cost
>
> Hi all!
>
> I think that actual train runing cost calculation can be more realistic.
> For
>
> example:
>
> Train runing cost = MC + LC * NL + WC * NW + AR * TS^2
>
> where:
>
> MC=Maquinist cost. This is a constant cost of 1 or 2 maquinists
> (traindrivers). Steam locomotives should have 2 maquinists per locomotive,
> electric and diesel engines should have only one per train, because
> multitraction won't need more traindrivers on electric and diesel
> locomotives.
>
> LC=Locomotive cost. This cost should be a variable cost, depending of % of
> power that a locomotive need for move a train. For example, a 5000cv
> locomotive with 2 wagons should have less running cost than a 5000cv
> locomotive with 10 wagons. Locomotives jumping mountains should have great
> runing cost than locomotives running on flat.
>
> NL=Number of locomotives.
>
> WC=Wagon cost: This is a constant cost for every train carriage.
>
> NW=Number of wagons
>
> AR=Air resistence: this is the costant aerodinamic resistence for a train.
> Inside tunnels this constant should be greater than outside.
>
> TS=Train Speed: Speed of train.

-- 
:: :: :: :: :: :: :: :: :: :: :: :: :: :: :: :: 
:: Jaume Sabater

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