Re: Question about IGMPv3 state change
Indranil Bhattacharya <[email protected]> Mon, 28 Feb 2011 18:56:31 +0530
| Newsgroups | gmane.ietf.magma |
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--===============1671420717== Content-Type: multipart/alternative; boundary=00163630f827c7c8c3049d57a0b9 --00163630f827c7c8c3049d57a0b9 Content-Type: text/plain; charset=ISO-8859-1 Hi Kunal, x = s1,s2 y= s3,s4 a=s2,s3 x+a = s1,s2,s3 y-a = s4 Does it answer your question? Thanks, Indranil On Tue, Feb 15, 2011 at 1:28 AM, Kunal Shah <[email protected]> wrote: > Hi all, > > I have a question about IGMPv3 state machine. If a group is in EX(X,Y) and > a TO_IN(A) is received, the new state according to the RFC is EX (X+A, Y-A). > I think this mean remove all the elements of A from Y and add all elements > of A to X. This also implies that sources not removed from Y will still end > up being added to X. My question is why cant we add only those elemets of A > to X which are removed from Y as opposed to adding all the elements of A to > X ?? > > If only the elements that are removed from Y are added to X, the new state > would look like EX (X+(Y*A), Y-A). > > Am I missing something here?? > > Kunal > > > _______________________________________________ > magma mailing list > [email protected] > https://www.ietf.org/mailman/listinfo/magma > > --00163630f827c7c8c3049d57a0b9 Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable <div>Hi Kunal,</div> <div>=A0</div> <div>=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0</div> <div>x =3D s1,s2</div> <div>y=3D s3,s4</div> <div>a=3Ds2,s3</div> <div>=A0</div> <div>x+a =3D s1,s2,s3</div> <div>y-a =3D s4<br></div> <div>Does it answer your question?</div> <div>=A0</div> <div>Thanks,</div> <div>Indranil</div> <div><br>=A0</div> <div class=3D"gmail_quote">On Tue, Feb 15, 2011 at 1:28 AM, Kunal Shah <spa= n dir=3D"ltr"><<a href=3D"mailto:[email protected]">kunal.shah@eri= csson.com</a>></span> wrote:<br> <blockquote style=3D"BORDER-LEFT: #ccc 1px solid; MARGIN: 0px 0px 0px 0.8ex= ; PADDING-LEFT: 1ex" class=3D"gmail_quote"> <div><font size=3D"2" face=3D"Arial, sans-serif"> <div>Hi all,</div> <div>=A0</div> <div>I have a question about IGMPv3 state machine. If a group is in EX(X,Y)= and a TO_IN(A) is received, the new state according to the RFC is EX (X+A,= Y-A). I think this mean remove all the elements of A from Y and add all el= ements of A to X. This also implies that sources not removed from Y will st= ill end up being added to X. My question is why cant we add only those elem= ets of A to X which are removed from Y as opposed to adding all the element= s of A to X ??</div> <div>=A0</div> <div>If only the elements that are removed from Y are added to X, the new s= tate would look like EX (X+(Y*A), Y-A). </div> <div>=A0</div> <div>Am I missing something here??</div> <div>=A0</div> <div>Kunal</div> <div>=A0</div></font></div><br>____________________________________________= ___<br>magma mailing list<br><a href=3D"mailto:[email protected]">[email protected]= rg</a><br><a href=3D"https://www.ietf.org/mailman/listinfo/magma" target=3D= "_blank">https://www.ietf.org/mailman/listinfo/magma</a><br> <br></blockquote></div><br> --00163630f827c7c8c3049d57a0b9-- --===============1671420717== Content-Type: text/plain; charset="us-ascii" MIME-Version: 1.0 Content-Transfer-Encoding: 7bit Content-Disposition: inline _______________________________________________ magma mailing list [email protected] https://www.ietf.org/mailman/listinfo/magma --===============1671420717==--