QoS NSLP Proxy mode

Roland Bless <[email protected]>
Newsgroups gmane.ietf.nsis
Organization Institute of Telematics, University of Karlsruhe
Message-ID <[email protected]>
Hi,

just a quick question for sec 4.8:
I find the dual use of the Proxy flag somewhat confusing.
In particular the draft says:

   For outgoing data flows and sender-initiated reservations, the end
   host is the QNI, and sends a RESERVE with the PROXY scope flag set.
   The P-QNE is the QNR, it will receive the RESERVE, notice the PROXY
   scope flag is set and reply with a RESPONSE (if requested).

a) How can an initiator know that a P-QNE will answer instead of the
   destination end host? (probably the have a prior appl. level
   signaling, but I think it would not be necessary to set the
   proxy bit in the RESERVE).

b) If there is the following use
   "certain region, e.g., for an administrative domain.  A node
   initiating the signaling may set the PROXY scope flag to indicate
   that the signaling is meant to be confined within the area controlled
   by the proxy, e.g., the local access network."
   it may actually conflict with the situation in a) where the QNI
   set the P-bit to indicate proxy use in its domain.

Assume A is the QNR and has to set the P-bit in the RESERVE because
B is not NSIS capable, then Domain 1 may use the P-bit
as scoping indication and drop the RESERVE?
   ---                ------
 /    \              /      \
|A   P |--> .... -->|   P    | B
 \    /              \      /
  ----                ------
Domain 1             Domain 2

My intuitive understanding of a proxy-mode would be:
QNI A sends a normal RESERVE and QNE P in Domain 2
intercepts the RESERVE and acts as proxy (P-QNE) for B.
Thus it sets the P-Bit in the RESPONSE (if one was requested).
A will see that P-bit is set and so conclude that it wasn't
really B who sent the RESPONSE. However, I don't see the
need that A must set the P-bit if the P-QNE in Domain 2
is configured to act as proxy for B.
Furthermore, I would recommend to remove the scope overloading
function of the P-bit as its use would be ambiguous.
Could someone clarify on that, please?

Regards,
 Roland
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