Re: I can has SHA-1 hashes for RFC 2409/3526 MODP groups?

On Fri, Mar 07, 2014 at 06:18:11PM -0500, Mouse wrote:
> 
> However, if you add 18 more 0s to the long string of them (which the
> formatting makes it look likely got dropped in whatever produced the
> weird line breaks above - if I add 18 more 0s and paste the first two
> lines together, the result is exactly as long as the next five lines),
> that _is_ 2^2048 - 2^1984 - 1 + (2^64 * 124476).  That is, it's what
> you get if you take pi to be 0.  I suspect your bc didn't recognize the
> character string "pi" and treated it as an unset variable or some such,
> effectively replacing it with 0.

If you want pi in bc, you need to start bc with the -l option and do:
pi=4*a(1)


Kurt