question about socket with link local addr

Hi,
    This looks like a very simple question,  but I don't know where do 
ask so I post it here.
I start my Mac, my "network" setting shows I have IP "10.1.1.157" since 
I am using DHCP,
I created a socket, try to connect to a linklocal addr say 
"169.254.80.220". now I find i am using IP "10.1.1.157" to connect 
obviously this is not what I want.

    Question is how do I create a socket on mac  such that the packet i 
send out shows my IP  LL addr?
    Thanks
mark


On Wednesday, July 2, 2003, at 04:47 AM, Philip Nye wrote:

>> From: "Robert Elz" <[email protected]>
>>
>>   | The use of "any" implies that two interfaces on the same host and
> connected
>>   | to the same link would not recognise each others ARPs as 
>> conflicts.
> This is
>>   | not independence.
>>
>> No, but nor does anything claim that the interfaces are independent.
>>
>> What it says is to run the algorithm independently on each interface.
>> That is: the order in which the two happen (including in parallel)
>> should be irrelevant, and the results of running the algorithm on the 
>> two
>> should in no way depend upon each other.   That's all it means.
>
> My issue is this:
>
> If I see a claim for an IP address I already have, then I should 
> recognise
> it as a conflict if and only if the claim appears on the interface to 
> which
> I have assigned that address.
>
> The fact that the hardware address for a conflicting claim matches one 
> of my
> other interfaces is spurious. It does however tell me that that other
> interface is connected to the same link and allows me to resolve the
> conflict internally if I wish (I could also avoid the conflict 
> internally
> before it ever occurs) but this is an implementation issue which need 
> not
> appear in the document.
>
> On the other hand, if the interfaces happen to be on different links 
> then
> seeing a claim for an address I already have on another interface, 
> should
> not be seen as a conflict - once again irrespective of hardware 
> address.
>