Re: Plan needed for switching m68k to 32-bit alignment

John Paul Adrian Glaubitz <[email protected]>
Newsgroups gmane.linux.debian.ports.68k,gmane.linux.ports.m68k
Message-ID <707333a8f10b92fd5c8fb3ad3dd928a5292215d2.camel@physik.fu-berlin.de>
Hi Arnd,

On Sun, 2024-10-27 at 13:15 +0000, Arnd Bergmann wrote:
> On Sun, Oct 27, 2024, at 06:16, Finn Thain wrote:
> > On Sun, 27 Oct 2024, Thorsten Glaser wrote:
> > 
> > > Finn Thain dixit:
> > > 
> > > > That would mean __alignof__(foo.b) == sizeof(foo.b) but that's not the
> > > > case on my Linux/i686 system. 4 != 8:
> > > > 
> > > > struct baa {
> > > >        int a;
> > > >        long long b;
> > > > } foo;
> > > 
> > > That struct is just 12 bytes for you then?
> > > 
> > 
> > Right. i686 and m68k agree on that.
> 
> The other ones that have misaligned 'long long' variables are
> 
> arc
> arm (OABI only)
> csky
> microblaze
> nios2
> openrisc
> superh
> i386
> 
> The 32-bit architectures that use a natural 8-byte
> alignment are
> 
> arm (EABI)
> parisc
> mips
> powerpc
> riscv
> s390
> sparc
> xtensa
> 
> m68k is the only architecture supported by linux-6.x that
> does 2-byte alignment, otherwise the two seem to be equally
> common.

Another useful data point. This is the kind of discussion I had hoped for!

Thanks a lot!

Adrian

-- 
 .''`.  John Paul Adrian Glaubitz
: :' :  Debian Developer
`. `'   Physicist
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