Re: How to end outgoing voice call in python
Michal Čihař <[email protected]> Thu, 30 Mar 2017 11:36:53 +0200
| Newsgroups | gmane.linux.drivers.gammu |
|---|---|
| Message-ID | <[email protected]> |
Sylvain píše v Čt 30. 03. 2017 v 11:24 +0200: > Le 30/03/2017 à 10:35, Michal Čihař a écrit : > > Hi > > > > Sylvain píše v St 29. 03. 2017 v 18:29 +0200: > > > I'm trying to make a program in python using gammu 1.37.4 > > > installed > > > on > > > ubuntu 16.04. The device I use is a Huawei E180 modem. > > > > > > I'm able to start a voice call with dialVoice, but I can't figure > > > out > > > how to stop or hang-up the call. I tried with Abort and Terminate > > > but > > > it > > > doesn't work, my program continues but the voice call is still > > > active. > > > Almost all call related functions are for incoming calls. > > > > > > Is it doable in python? Any pointers? > > > > CancelCall should do that: > > > > https://wammu.eu/docs/manual/python/gammu.html#gammu.StateMachine.C > > ance > > lCall > > > > I tried but it requires the ID of the call as parameter but > DialVoice > only returns None. I see a lot of functions that use the ID of the > call > as parameter but none that returns it. How can I get the call ID? Use anything as call ID and pass True as second parameter. That should do it. -- Michal Čihař | https://cihar.com/ | https://weblate.org/ ------------------------------------------------------------------------------ Check out the vibrant tech community on one of the world's most engaging tech sites, Slashdot.org! http://sdm.link/slashdot _______________________________________________ Gammu-users mailing list - https://lists.sourceforge.net/lists/listinfo/gammu-users
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