Re: Converting 1276290588 to readable date/time

[email protected] Mon, 14 Jun 2010 13:08:30 -0500
Newsgroups gmane.linux.mandrake.newbie
Message-ID <[email protected]>
There are many ways to do that.  That number is the number of seconds
elapsed since epoch (Midnight, Jan 1, 1970).

You can use a complex math formula including Zeller's congruence or you
can use a language that already knows how to convert epochal time....


Here it is in Python

>>> import time
>>> x=time.time()
>>> x
1276538631.151
>>> time.localtime(x)
time.struct_time(tm_year=2010, tm_mon=6, tm_mday=14, tm_hour=10, tm_min=3,
tm_se
c=51, tm_wday=0, tm_yday=165, tm_isdst=1)
>>> time.asctime(time.localtime(x))
'Mon Jun 14 10:03:51 2010'
>>>

Margrave


> I forgot how to do this, any help appreciated.
>
> --
> Chris
> KeyID 0xE372A7DA98E6705C
>
>


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