RE: Fgets is not working on linux/gcc3.2.1

Headers like?? 


-----Original Message-----
From: Michael Schwendt [mailto:[email protected]] 
Sent: Thursday, April 10, 2003 1:30 PM
To: [email protected]

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On Thu, 10 Apr 2003 12:01:24 +0530, Ajay Bansal wrote:

> Following program is not working on linux. Ideally it should read all 
> the lines from "/tmp/log.txt" and print them on to the screen.

The given source code example does not match this description.

Apart from that it would not even compile, because you forgot to include
a few headers.

> Instead
> it breals after it encounters fgets for the first time.
> Pleas tell me where I am going wrong!!!! This program is working as 
> expected on a Solaris machine.

I doubt that. See below.

> Entries in log.txt
> ------------------
> Line1
> Line2
> Line3
> ------------------
> 
> Output of the program
> ---------------------
> [ajay@linux1 test]$ ./a.out
> Fileno is :3
> Error no is : 0
> Error is : Success
> Line read is : 
>  after fgets break outside while loop
> ---------------------
> 
> #include <iostream>
> #include <fstream>
> #include <errno.h>
> #include <stdlib.h>
> using namespace std;
> int main()
> {
>     char * pszFileName = "/tmp/log.txt";
>     char * pszMode = "a+";

!!!

>     char lpsz[4096];
>     FILE *pFile = fopen(pszFileName, pszMode);

Due to pszMode above, this opens the file at the end.
Therefore it doesn't read the contents of the file.

>     while (!feof(pFile)) {
>         if (! fgets(lpsz, 4096, pFile))
>         {
>             cout<<"Error no is : "<<errno<<endl;
>             cout<<"Error is : "<<strerror(errno)<<endl;
>             cout<<"Line read is : "<<lpsz<<endl;
>             break;
>          }
> 	   cout<<"Line read is : "<<lpsz<<endl; 
>     	   cout <<" after fgets break inside while loop"<<endl;
>     }
> 
>     cout <<" after fgets break outside while loop"<<endl;
> 
>     return 1;
> }

- --
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