Re: ip command line question
Ryan McDougall <[email protected]>
| Newsgroups | gmane.linux.redhat.release.psyche |
|---|---|
| Message-ID | <[email protected]> |
--- Stephen Liu <[email protected]> wrote: > Hi all folks Hi > On issuing following command > > # ip addr > 1: lo: <LOOPBACK,UP> mtu 16436 qdisc noqueue > link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 > inet 127.0.0.1/8 brd 127.255.255.255 scope host lo > 2: eth0: <BROADCAST,MULTICAST,UP> mtu 1500 qdisc pfifo_fast qlen 100 > link/ether 00:50:fc:39:3b:59 brd ff:ff:ff:ff:ff:ff > 3: ppp0: <POINTOPOINT,MULTICAST,NOARP,UP> mtu 1492 qdisc pfifo_fast qlen > 3 > link/ppp > inet 202.123.68.48 peer 202.123.71.254/32 scope global ppp0 > > What does point 3. above indicate? It indicates that you are connecting to the net via the Point to Point Protocol. And this is usually used with some sort of DSL. > What command line to be issued to find the current ip address assigned > by ISP (broadband)? Actually the ip address is in point 3: "inet 202.123.68.48 peer 202.123.71.254/32 scope global ppp0" This inet line tells you your ip address, 202.123.68.48 > Thanks in advance. > > B.Regards > Stephen Liu Hope That Helps Ryan __________________________________ Do you Yahoo!? SBC Yahoo! DSL - Now only $29.95 per month! http://sbc.yahoo.com -- Psyche-list mailing list [email protected] https://www.redhat.com/mailman/listinfo/psyche-list