Re: rpm scoring script.

On Sun, 2004-02-15 at 18:28, seth vidal wrote:
> not too hard to do - if you take the code from yum-arch you can do 70%
> of this.
> 
> 1. get a list of all the rpms
> 2. start going through each one and make a couple of dicts:
>  (name, arch) : [(e, v, r), (e, v, r)]
>  (name, arch, e, v, r) : pkg filename
> 
> 3. then go through each (name, arch) in the first dict and if the len of
> the list of (e, v, r) is > 1 then compare each (e, v, r) and remove the
> one(s) that are older.
> 
> 4. then go through the second dict using the first and copy out the rpms
> that are newest.

Thanks I will give that a go. 

Mike