Re: how to compute

      From: Yaling Zheng <[email protected]>

      Does any one know how to calculate the exact value of the ratio (such
      as 6042715942219502152353483497843569525253244555916134 over 200)?

      CL-USER(68): (float (/ 6042715942219502152353483497843569525253244555916134 200))
      #.EXCL::*INFINITY-SINGLE*

   From: "Bob Giansiracusa" <[email protected]>

   Sure.  Use bignums:

   (/ 6042715942219502152353483497843569525253244555916134 200)

This is indeed the "exact" answer.  But if your intended meaning of
"exact" was really "a floating-point approximation" (:-) then you must
first realize that the numeric value is outside the range of
single-float.  But if the ratio it is still within the range of
double-float you might compute a double-float approximation this way:

cl-user(11): (let* ((rat (/ 6042715942219502152353483497843569525253244555916134 200))
		    (num (coerce (numerator rat) 'double-float))
		    (den (coerce (denominator rat) 'double-float)))
	       (/ num den))
3.0213579711097513d+49