Re: sorted?

On Mon, Dec 09, 2024 at 11:37:33AM +0000, Ricardo G. Herdt wrote:
> Hi Jeremy,
> 
> Am 09.12.2024 11:21 schrieb Jeremy Korwin-Zmijowski:
> > The reference says :
> > 
> >    Scheme Procedure: *sorted?* items less
> >    C Function: *scm_sorted_p* (items, less)
> > 
> >        Return |#t| if items is a list or vector such that, for each
> >        element x and the next element y of items, |(less y x)| returns
> >        |#f|. Otherwise return |#f|.
> > 
> > I think the description should be :
> > 
> >    Return |#t| if items is a list or vector such that, for each element
> >    x and the next element y of items, |(less y x)| returns |#t|.
> >    Otherwise return |#f|.
> 
> Actually no, since less is applied to y and x in that order. This way
> (sorted? '(1 1) <) correctly returns #t as your experiments show.

I don't get it. (< 1 1) is /always/ #f, regardless of the order of the
ones?

I'm as confused as Jeremy is.

Cheers
-- 
tomás

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