Re[2]: sorted?

------ Original Message ------
From [email protected]
To [email protected]
Date 09.12.2024 12:42:22
Subject Re: sorted?

>On Mon, Dec 09, 2024 at 11:37:33AM +0000, Ricardo G. Herdt wrote:
>>  Hi Jeremy,
>>
>>  Am 09.12.2024 11:21 schrieb Jeremy Korwin-Zmijowski:
>>  > The reference says :
>>  >
>>  >    Scheme Procedure: *sorted?* items less
>>  >    C Function: *scm_sorted_p* (items, less)
>>  >
>>  >        Return |#t| if items is a list or vector such that, for each
>>  >        element x and the next element y of items, |(less y x)| returns
>>  >        |#f|. Otherwise return |#f|.
>>  >
>>  > I think the description should be :
>>  >
>>  >    Return |#t| if items is a list or vector such that, for each element
>>  >    x and the next element y of items, |(less y x)| returns |#t|.
>>  >    Otherwise return |#f|.
>>
>>  Actually no, since less is applied to y and x in that order. This way
>>  (sorted? '(1 1) <) correctly returns #t as your experiments show.
>
>I don't get it. (< 1 1) is /always/ #f, regardless of the order of the
>ones?
>
>I'm as confused as Jeremy is.
>

I understand the reference text as "Return #t if the list is _not 
unsorted_".
Since (< 1 1) returns #f, '(1 1) is _not unsorted_ and all is well.

s.