Re: how to allocate an array of C structs?

I see, thanks Joe, that's right.  Sorry for taking awhile to respond. 
Still though, it may be a little inconvenient to create a new name just 
for the typename of the dynamically allocable struct.  However, this 
workaround is definitely functional.

Thanks and regards,
Rory


On Mon, 19 Oct 2015, Joseph Donaldson wrote:

> Hello, Rory,
> 
> Using your aStruct.h, the code below works for me. I believe the problem 
> with the original code is name clash between your bigloo struct and 
> pointer declarations. The struct declaration creates a type named 
> myStruct* which masks your pointer type declaration using the same name.
> 
> Best Regards,
> Joe
> 
>  
> (module cstructarrays
>    (main main)
>    (extern
>       (include "aStruct.h")
>       (type myStruct (struct
> (elt1::int "elt1")
>                          (elt2::int "elt2")
>                          (elt3::int "elt3")
>                          ) "myStruct")
>       (type myStructArr (pointer myStruct) "myStruct*")))
> 
> 
> (define (main args)
>    (let ((arr (make-myStructArr 4)))
>       (do ((i 0 (+ i 1)))
>  ((= i 4))
>  (myStruct*-elt1-set! (myStructArr-ref arr i) i))
>       (do ((i 0 (+ i 1)))
>  ((= i 4))
>  (print (myStruct*-elt1 (myStructArr-ref arr i))))))
> 
> 
> ___________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
>       From: Rory Mulvaney <[email protected]>
>       To: [email protected]
>       Sent: Tuesday, October 13, 2015 8:22 AM
>       Subject: [bigloo] how to allocate an array of C structs?
> 
> Bigloo community,
> 
> I don't see a way to allocate an array of C structs.  If I have a C struct
> called "myStruct", I think I should be able to use (make-myStruct* 3) to
> return a pointer to a newly-allocated array of 3 myStructs.  However, it
> seems the only way to allocate a new C struct is to allocate them 1 at a
> time, using (myStruct* elt1 elt2 elt3).
> 
> http://www-sop.inria.fr/members/Manuel.Serrano/bigloo/doc/bigloo-28.html#The-C-interface
> (see sections on Struct and Union types and section on C pointers)
> 
> This is what I have:
> 
> [aStruct.h:
> 
> typedef struct myStruct {
>   int elt1;
>   int elt2;
>   int elt3;
> } myStruct;
> 
> ]//end of aStruct.h
> 
> (module aStruct
>         (main testAStruct)
>         (extern
>         (include "aStruct.h")
>         (type myStruct (struct
>                         (elt1::int "elt1")
>                         (elt2::int "elt2")
>                         (elt3::int "elt3")
>                         ) "myStruct")
>         ;; automatically defined
>         ;; (type myStruct* (pointer myStruct) "myStruct*")
>         )
>         )
> 
> (define (testAStruct argv)
>   ; doesn't work                                                             
>   ; (make-myStruct* 3)                                                       
>   ; works                                                                     
>   (myStruct* 1 2 3)
> 
> )
> 
> Thanks and regards,
> Rory
> 
> 
> 
>