Hi James,
> Hi Manuel,
>
> On Wed, Sep 20, 2017 at 10:41 PM, <[email protected]> wrote:
> > What do you mean? What do you think is wrong?
>
> I just meant that even on little endian architectures, the consuming
> code is reading only 32 bits of a 64-bit value. It doesn't break
> anything, because it happens to be reading the "right" 32 bits, and
> the "wrong" 32 bits happen to be zero. If they weren't zero, that is
> if the code were to process a value greater than 4294967295 (or
> 2147483647 for signed values), then the code would do the wrong thing
> even on little endian architectures.
Thanks for the explanation but I'm not certain to know which code you
are refereeing to. The code that you have patched recently?
--
Manuel
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