namespace-variable-value thinks functions are bound to syntax

Hello list,

In the following program, racket thinks foo2, and foo3 are bound to
syntax. Is this expected behavior?

-- File: go.rkt

#lang racket

(module p racket
  (provide (all-defined-out))

  (define (foo0 a b)
    (+ a b))
  (define (foo1 a b [c 3])
    (+ a b c))
  (define (foo2 a b [c 3] #:kw1 kw1)
    (+ a b c))
  (define (foo3 a b [c 3] #:kw1 kw1 #:kw2 [kw2 1])
    (+ a b c))
  )

(require syntax/location)

(define ns (make-base-empty-namespace))
(parameterize ([current-namespace ns])
  (namespace-require (quote-module-path p)))

(namespace-variable-value 'foo0 #t #f ns) ; OK
(namespace-variable-value 'foo1 #t #f ns) ; OK
(namespace-variable-value 'foo2 #t #f ns) ; namespace-variable-value:
bound to syntax in: foo2
(namespace-variable-value 'foo3 #t #f ns) ; namespace-variable-value:
bound to syntax in: foo3

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