Re: update on the djbdns bugs? (fwd)

Joe Baptista <[email protected]>
Newsgroups gmane.network.djbdns
Message-ID <[email protected]>
Dean - the whole crap shoot with Kaminsky & Vixie & company was one big
marketing scam to scar the world into the DNSSEC marketing make work scam.

I found Kaminsky bug claims an embarrassment considering the bug itself was
fixed by Bernstein many years before.

I'm surprised these guys manage to get away with this bullshit and have a
good shot at getting the world into the DNSSEC straight jacket.

regards
joe baptista

On Wed, Mar 10, 2010 at 8:50 PM, Dean Anderson <[email protected]> wrote:

>
> Yep, that "*" instead of "/" was a mistake I caught at the time, just
> after I sent the email to Kaminsky and Day.
>
> But the "roulette logic" that Kaminsky asserts is complete BS, which if
> you read the whole thread, is what counts.  I got the math right.
> Kaminsky and Day just made up "roulette logic".  It comes within an
> order of magnitude of the right number in this case, but is wildly wrong
> in other cases (different number of items selected, different urn size)
>
>                --Dean
>
> On Wed, 10 Mar 2010, Matthew Dempsky wrote:
>
> > On Wed, Mar 10, 2010 at 3:40 PM, Dean Anderson <[email protected]> wrote:
> > >> Dean, I was using simple roulette logic.  65,536 ports * 65,536 qids /
> > >> 200 simultaneously valid responses = 21M.  We're dealing in orders of
> > >> magnitudes, it's a reasonable approximation.
> > >
> > > You still seem to be channeling Palin:
> > >
> > > (%i69) 65536 * 65536 * 200;
> > > (%o69)                           858993459200
> > >
> > > Quite a bit higher than 21M.
> >
> > For anyone thinking Dean deserves any credibility on this issue, take
> > a look at just this simple example: Dan Kaminsky is pointing out that
> > 65536 * 65536 / 200 = 21M, but Dean counters by pointing out that
> > 65536 * 65536 _*_ 200 != 21M.
> >
> > > But you have no credible explanation for your math.
> >
> > Further, the math behind Dan's number is straight forward: an attacker
> > has to guess two 16-bit numbers (i.e., the 65536 * 65536), but there
> > are 200 winning pairs to choose from (i.e., the 200 outstanding
> > queries for identical names).  Having more winning pairs means the
> > number of expected guesses before success *decreases* (i.e.,
> > division), not increases (i.e., multiplication).
> >
> >
>
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