Re: update on the djbdns bugs? (fwd)
Joe Baptista <[email protected]>
| Newsgroups | gmane.network.djbdns |
|---|---|
| Message-ID | <[email protected]> |
Dean - the whole crap shoot with Kaminsky & Vixie & company was one big marketing scam to scar the world into the DNSSEC marketing make work scam. I found Kaminsky bug claims an embarrassment considering the bug itself was fixed by Bernstein many years before. I'm surprised these guys manage to get away with this bullshit and have a good shot at getting the world into the DNSSEC straight jacket. regards joe baptista On Wed, Mar 10, 2010 at 8:50 PM, Dean Anderson <[email protected]> wrote: > > Yep, that "*" instead of "/" was a mistake I caught at the time, just > after I sent the email to Kaminsky and Day. > > But the "roulette logic" that Kaminsky asserts is complete BS, which if > you read the whole thread, is what counts. I got the math right. > Kaminsky and Day just made up "roulette logic". It comes within an > order of magnitude of the right number in this case, but is wildly wrong > in other cases (different number of items selected, different urn size) > > --Dean > > On Wed, 10 Mar 2010, Matthew Dempsky wrote: > > > On Wed, Mar 10, 2010 at 3:40 PM, Dean Anderson <[email protected]> wrote: > > >> Dean, I was using simple roulette logic. 65,536 ports * 65,536 qids / > > >> 200 simultaneously valid responses = 21M. We're dealing in orders of > > >> magnitudes, it's a reasonable approximation. > > > > > > You still seem to be channeling Palin: > > > > > > (%i69) 65536 * 65536 * 200; > > > (%o69) 858993459200 > > > > > > Quite a bit higher than 21M. > > > > For anyone thinking Dean deserves any credibility on this issue, take > > a look at just this simple example: Dan Kaminsky is pointing out that > > 65536 * 65536 / 200 = 21M, but Dean counters by pointing out that > > 65536 * 65536 _*_ 200 != 21M. > > > > > But you have no credible explanation for your math. > > > > Further, the math behind Dan's number is straight forward: an attacker > > has to guess two 16-bit numbers (i.e., the 65536 * 65536), but there > > are 200 winning pairs to choose from (i.e., the 200 outstanding > > queries for identical names). Having more winning pairs means the > > number of expected guesses before success *decreases* (i.e., > > division), not increases (i.e., multiplication). > > > > > > -- > Av8 Internet Prepared to pay a premium for better service? > www.av8.net faster, more reliable, better service > 617 256 5494 > > >