Re: bash array names with variables

From what I've read bash doesn't support 2 dimensional arrays, however
there are a few tricks you can find at the link below.

http://www.commandlinefu.com/commands/view/7921/tricky-implementation-of-two-dimensional-array-in-bash
.
On Oct 22, 2012 11:49 AM, "Tim Holloway" <timh-kiPKLF+HnOy1Z/[email protected]> wrote:

> 2 dimensional arrays: e.g. a[$i][$j] = "X"
>
> ???
>
>     Tim
>
> On Sat, 2012-10-20 at 23:37 -0400, Robert Mckennon wrote:
> > Is it possible to use a variables in an array name?
> >
> > I'm having a hell of a time getting it to work.
> >
> > for instance:   a_0[x], a_1[x]...etc  defined as: a_$i[x]
> >
> > I use a loop to create the arrays a_$i
> > and then try and access them with:
> >
> > arrayname=a_$i
> > nextarray=a_$(( $i + 1 ))
> >
> >
> > I found I can get the data out of an array with a variable-name like
> > so:   F[$i]=$(eval echo \${$arrayname[$N]})
> >
> > and that works... (found that tip here
> >
> http://www.linuxquestions.org/questions/programming-9/bash-loop-over-variable-array-names-705702/
> > )
> >
> >
> > But when trying to put data into the variable-named arrays is where
> > I'm running into issues.
> >
> >     52      if [ $j != $N ];
> >     53       then
> >     54        {
> >     55        $nextarray[$k]=$(eval echo \${$arrayname[$j]})
> >     56        k=$(( $k + 1 ))
> >     57        }
> >     58      fi
> >
> >    ./random.sh: line 55: a_4[0]=: command not found
> >
> > I've tried escaping it every way I can think of and google for, but
> > I'm about done banging my head against the wall...
> >
> >
> > Any suggestions???
> >
> > Rob.
> >
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