Re: Do we need Perl -arch wrappers for 10.7+ ?

On Tue, November 11, 2014 2:48 pm, Alexander Hansen wrote:
> Here’s an example from the bootstrap script:
>
> my $perlexe  = "/usr/bin/perl"; #default
> # override defaults
> if ($distribution eq "10.6") {
> 	$perlexe = "/usr/bin/arch -arch $arch /usr/bin/perl5.10.0";
> } elsif (($distribution eq "10.7") or ($distribution eq "10.8")) {
> 	$perlexe = "/usr/bin/arch -arch $arch /usr/bin/perl5.12";
> } elsif ($distribution eq "10.8") {
> 	$perlexe = "/usr/bin/arch -arch $arch /usr/bin/perl5.16";
> } elsif (($arch eq "x86_64") and ($distribution eq "10.5")) {
> 	$perlexe = "$bsbase/bin/perl5.8.8";
> }
>
> There are 2 issues:
>
> 1) It’s using perl5.16 for 10.10.
> 2) Do we *need* the -arch wrappers for 10.7+ at all?  Is there any reason
> not just to use the default?

Also the second 10.8 check is a typo that should be for 10.9 (perl5.16).

Hanspeter

-- 
More agile than a turtle, stronger than a mouse, nobler than a lettuce


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