Re: Help with Interpretation
"Frank D. Engel, Jr." <[email protected]> Sun, 5 Jan 2020 19:19:56 -0500
| Newsgroups | gmane.os.plan9.general |
|---|---|
| Message-ID | <[email protected]> |
Thanks! I built the file server using a 32-bit 386 kernel but I think 64-bit=20 CWFS was used?=C2=A0 I will try to figure out somehow which block size was= =20 selected, and that gives me something to work with. Looks like it is just under 1 GB used if I have the 4K block size, and=20 just under 2 GB used if I have the 8K block size, of a 64.21 GB worm=20 partition. On 1/5/20 10:56 AM, Steven Stallion wrote: >> I am trying to make sense of these numbers but having some difficulty >> finding any documentation explaining them. > Your best bet is to read the source in /sys/src/cmd/cwfs; cwfs is a > ported version of the original file server, ie. Ken's. > >> Can someone either point me to that documentation or walk me through how >> to interpret this? > Ken's can be a little terse, but the out put is very meaningful; fsize > is what you care about in this context. This is the number of blocks > used by the WORM. Take this number and multiply it by RBUFSIZE to get > the number of bytes written to disk. Assuming you're using a 64-bit > fileserver, this will be 8K by default (4K for 32-bit), but this > depends on the kernel you are using. >=20 > HTH, > Steve >=20 ------------------------------------------ 9fans: 9fans Permalink: https://9fans.topicbox.com/groups/9fans/Ta16a4beaa5de93c0-M77210= e62cd5d01afd0dd0b78 Delivery options: https://9fans.topicbox.com/groups/9fans/subscription