[AlbClub] Për partitë e vogla, brenda Kushte tutës
"Bashkim Kopliku--->Gmail Home" <[email protected]> Sun, 31 Aug 2008 08:46:47 +0200
| Newsgroups | gmane.recreation.alb-club,gmane.spam.detected |
|---|---|
| Message-ID | <003201c90b35$60a04c20$0401a8c0@pc> |
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*** AlbClub Discussion List ***
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P=EBr partit=EB e vogla, brenda Kushtetut=EBs
[Gazeta Shqiptare, 31.8.2008]
Po thon=EB se n=EB shtator, puna e par=EB me t=EB cil=EBn do t'u marrka K=
uvendi, qenka=20
b=EBrja e Kodit Zgjedhor (KZ). Natyrisht q=EB KZ do t=EB b=EBhet n=EB p=EB=
rputhje me=20
kushtetut=EBn aktuale, pra p=EBr nj=EB sistem zgjedhor "me zona zgjedhore=
=20
shumem=EBrore", apo rajonal (SZPR). Por brenda SZPR, n=EB bot=EB p=EBrdo=
ren disa=20
metoda p=EBr p=EBrcaktimin e numrit t=EB deputet=EBve p=EBr secil=EBn par=
ti n=EB secil=EBn=20
zon=EB. K=EBto metoda nuk jan=EB p=EBrcaktuar n=EB Kushtetut=EBn ton=EB:=
jan=EB l=EBn=EB t=EB=20
p=EBrcaktohen n=EB KZ. Numri i deputet=EBve q=EB do t=EB marr=EB secila =
parti n=EB=20
secil=EBn zon=EB, varet edhe nga metoda q=EB do t=EB p=EBrdoret: ka meto=
da q=EB=20
favorizojn=EB n=EB nj=EB far=EB mase partit=EB e vogla, e ka q=EB favoriz=
ojn=EB partit=EB e=20
m=EBdha. N=EB rastin ton=EB, do t=EB ishte mir=EB t=EB zgjidhet metoda q=
=EB favorizon=20
partit=EB e vogla, gj=EB q=EB do t=EB kompensonte, sado pak, goditjen q=EB=
iu dha=20
partive t=EB vogla-goditje q=EB iu dha edhe demokracis=EB n=EB rastin kon=
kret t=EB=20
Shqip=EBris=EB-nga ndryshimi i Kushtetut=EBs, kur u kalua n=EB sistemin r=
ajonal. Po=20
p=EBr k=EBt=EB arsye, duhet q=EB zonat zgjedhore t=EB zgjidhen mbi baz=EB=
n e "ndarjes=20
administrative t=EB nivelit m=EB t=EB lart=EB, t=EB organizimit=20
administrativo-territorial", q=EB t=EB kemi sa m=EB pak zona, gj=EB q=EB =
do t=EB=20
zvog=EBlonte, n=EB nj=EB far=EB mase, edhe pragun zgjedhor efektiv.
zonat zgjedhore dhe numri i Vendeve n=EB kuvend
Numri i zonave zgjedhore duhet t=EB jet=EB 12. Kjo sepse n=EB Kushtetut=EB=
=20
shkruhet: "Zona zgjedhore shumem=EBrore p=EBrputhet me ndarjen administra=
tive t=EB=20
nj=EB prej niveleve t=EB organizimit administrativo-territorial.". Numri=
n m=EB t=EB=20
vog=EBl t=EB zonave, do ta kishim duke marr=EB zon=EBn zgjedhore t=EB p=EB=
rputhur me=20
prefektur=EBn, pra 12 zona-nuk b=EBhen dot edhe m=EB pak, gj=EB q=EB do t=
=EB ishte shum=EB=20
e preferueshme.
P=EBr t=EB p=EBrcaktuar sesa vende do t=EB ket=EB n=EB Kuvend, secila zon=
=EB, do t=EB=20
propozonim metod=EBn q=EB vijon.
N=EB baz=EB t=EB rezultatit t=EB zgjedhjeve, p=EBrcaktohen votat e vlefsh=
me q=EB jan=EB=20
marr=EB n=EB =E7do zon=EB zgjedhore (VZ, votat e zon=EBs) dhe votat e vle=
fshme n=EB t=EB=20
gjith=EB vendin (VV, votat e vendit). Shum=EBzohet p=EBr =E7do zon=EB, V=
Z me 140=20
(numri gjithsej i vendeve n=EB Kuvend), dhe ky produkt pjes=EBtohet me VV=
, nga=20
ku merret numri proporcional i votave t=EB zon=EBs (NPVZ, numri proporcio=
nal i=20
votave t=EB zon=EBs). Ja formula:
NPVZ=3DVZ x 140 / VV
NPVZ =EBsht=EB nj=EB num=EBr dhjetor, pra q=EB ka pjes=EBn e plot=EB, dhe=
pjes=EB dhjetore.=20
Supozojm=EB se NPVZ-t=EB e zonave rezultojn=EB 54, 35 e 5, 23 etj. Pjes=EB=
t e plota=20
t=EB NPVZ-ve jan=EB p=EBrkat=EBsisht 54; e me radh=EB 5 etj. Pjes=EBt dh=
jetore jan=EB=20
p=EBrkat=EBsisht 0,35 e 0,23 etj.
Fillimisht i jepet =E7do zone aq vende n=EB Kuvend, sa =E7'=EBsht=EB pjes=
a e plot=EB e=20
NPVZ-s=EB s=EB saj. P.sh. 54 vende, zona tjet=EBr 5 vende etj. Mblidhen=
vendet=20
q=EB u ndan=EB mbi baz=EBn e pjes=EBs s=EB plot=EB n=EB numrave t=EB zona=
ve n=EB t=EB gjith=EB=20
vendin. E z=EBm=EB se dol=EBn 136 vende. B=EBhet diferenca e k=EBsaj sh=
ume, me=20
numrin 140 (vendet gjithsej n=EB Kuvend), q=EB n=EB shembullin ton=EB =EB=
sht=EB 4 vende.=20
K=EBto vende t=EB diferenc=EBs, u shp=EBrndahet nga nj=EB atyre zonave q=EB=
kan=EB pjes=EBn=20
dhjetore relative m=EB t=EB madhe.
Pjesa dhjetore relative (PDhR), llogaritet p=EBr secil=EBn zon=EB, duke p=
jes=EBtuar=20
pjes=EB dhjetore me pjes=EBn e plot=EB plus 1. K=EBshtu, n=EB shembullin=
ton=EB, pjes=EBt=20
dhjetore relative jan=EB 0,0064 (0.35/55), apo 0,038 (0.23/6) etj. Zonat=
=20
rreshtohen sipas PDhR, nga m=EB e madhja deri tek m=EB e vogla.
Ju shp=EBrndahet nga nj=EB vend n=EB Kuvend, vet=EBm zonave t=EB para, n=EB=
shembullin=20
ton=EB vet=EBm 4 zonave t=EB para. Pra, vendet i marrin ato zona q=EB ka=
n=EB pjes=EBt=20
dhjetore relative, m=EB t=EB m=EBdha (p.sh., 0,038 =EBsht=EB m=EB e madhe=
se 0,0064).
K=EBshtu tashm=EB kemi p=EBrcaktuar numrin e vendeve n=EB Kuvend t=EB =E7=
do zone (NVKZ),=20
i cili, si=E7 e shpjeguam, =EBsht=EB sa pjesa e plot=EB e NPVZ, e shtuar =
me 1 vend,=20
n=EBse i takon nga shp=EBrndarja e diferenc=EBs s=EB vendeve t=EB Kuvendi=
t me shum=EBn e=20
pjes=EBve t=EB plota t=EB NPVZ-ve.
Numri i Deputet=EBve t=EB secil=EBs parti n=EB secil=EBn zon=EB
NVKZ ndahen p=EBr =E7do parti, sipas votave q=EB ka marr=EB n=EB zon=EB, =
po sipas=20
propozimit t=EB m=EBsip=EBrm.
Votat e vlefshme q=EB ka marr=EB =E7do parti n=EB zon=EB (VPZ, votat e pa=
rtis=EB n=EB=20
zon=EB), shum=EBzohen me NVKZ (pra me numrin e vendeve n=EB Kuvend q=EB i=
takojn=EB=20
zon=EBs), si=E7 u llogarit=EBn m=EB lart, dhe produkti pjes=EBtohet me vo=
tat e marra=20
gjithsej nga t=EB t=EBra partit=EB n=EB at=EB zon=EB (VTZ, votat t=EBr=EB=
sore n=EB zon=EB). Nga=20
ky pjes=EBtim, merret p=EBr =E7do parti, numri proporcional i deputet=EBv=
e t=EB saj n=EB=20
zon=EB (NPDPZ, numri proporcional i deputet=EBve t=EB partis=EB n=EB zon=EB=
). Ja=20
formula:
NPDPZ=3DVPZ x NVKZ / VTZ
NPDPZ =EBsht=EB nj=EB num=EBr dhjetor, q=EB ka pjes=EBn e plot=EB, dhe pj=
es=EB dhjetore.=20
Fillimisht i jepet =E7do partie deputet=EB, sa =E7'=EBsht=EB pjesa e plot=
=EB e NPDPZ.=20
Mblidhen deputet=EBt q=EB u caktuan mbi baz=EBn e pjes=EBs s=EB plot=EB t=
=EB NPDPZ. B=EBhet=20
diferenca e k=EBsaj shume, me NVKZ (numrin e vendeve q=EB i takojn=EB asa=
j zone n=EB=20
Kuvend).
K=EBto deputet=EB t=EB diferenc=EBs, u shp=EBrndahen nga nj=EB atyre part=
ive q=EB kan=EB=20
pjes=EBn dhjetore relative (PDhR) m=EB t=EB madhe.
PDhR llogaritet p=EBr secil=EBn parti, duke pjes=EBtuar pjes=EB dhjetore =
me pjes=EBn e=20
plot=EB plus 1 (q=EB t=EB mund t=EB merren parasysh edhe ato parti q=EB k=
an=EB numrin e=20
plot=EB zero). Partit=EB n=EB zon=EB rreshtohen sipas PDhR, nga m=EB e m=
adhja deri=20
tek m=EB e vogla.
Ju shp=EBrndahet nga nj=EB deputet, vet=EBm partive t=EB para. Pra, marr=
in edhe nga=20
nj=EB deputet, ato parti q=EB kan=EB pjes=EBt dhjetore relative m=EB t=EB=
m=EBdha.
K=EBshtu tashm=EB kemi p=EBrcaktuar numrin e deputet=EBve p=EBr =E7do par=
ti n=EB =E7do zon=EB,=20
e p=EBrs=EBrisim: si shum=EB e deputet=EBve t=EB llogaritur sipas numrit =
t=EB plot=EB, me=20
deputet=EBt q=EB mund t'i takoj=EB nga shp=EBrndarja e diferenc=EBs.
Emrat konkret=EB t=EB deputet=EBve dalin duke marr=EB nga listat emrat e =
rreshtuar=20
t=EB par=EBt.
Nj=EB shembull hipotetik
Kemi b=EBr=EB disa llogaritje t=EB nj=EB zone hipotetike (t=EB mundshme) =
n=EB zgjedhjet=20
e vitit 2009, t=EB cilat i kemi p=EBrmbledhur n=EB tabel=EBn e m=EBposhtm=
e. Zona=20
=EBsht=EB me 12 vende n=EB Kuvend. Kemi p=EBrpunuar rezultatin e zgjedhj=
eve me=20
metod=EBn e propozuar, t=EB shpjeguar m=EB lart. N=EB tri kolonat e fund=
it, kemi=20
dh=EBn=EB numrin e deputet=EBve t=EB llogaritur edhe sipas tri metodave t=
=EB p=EBrdorura=20
gjer=EBsisht n=EB bot=EB: metod=EBs Webster (ose Sainte Lagu=EB&Schepers,=
q=EB p=EBrdoret=20
sot n=EB Gjermani), metod=EBs Hamilton (ose Hare-Niemeyer, q=EB =EBsht=EB=
p=EBrdorur n=EB=20
Gjermani deri para nj=EB viti) dhe metod=EBs s=EB D'Hondt (p=EBrdoret n=EB=
Spanj=EB).
Vini re se "partia e vog=EBl" sipas metod=EBs s=EB propozuar, merr nj=EB =
deputet=20
(edhe sipas Hamilton), kurse sipas dy metodave t=EB tjera nuk merr asnj=EB=
.=20
Edhe partia mesatare, merr dy deputet=EB sipas metod=EBs s=EB propozuar (=
dhe=20
Hamilton), por merr vet=EBm nj=EB deputet sipas metod=EBs Webster dhe asa=
j D'Hondt.
* * *
Sa shpjeguam =EBsht=EB vet=EBm nj=EB propozim. Kuvendi duhet t=EB filloj=
=EB t=EB punoj=EB=20
intensivisht p=EBr t=EB p=EBrcaktuar metod=EBn konkrete, por pa u fshehur=
pas=20
diskutimeve dhe q=EBndrimeve t=EB p=EBrgjithshme.
Bashkim Kopliku
29.8.2008
PS-P=EBr nj=EB gabim teknik, nuk =EBsht=EB publikuar tabela dhe "shembull=
i=20
hipotetik".
Phone: +355 52 223663
Mob: +355 682200590
E-mail: <[email protected]>
optional: <[email protected]>
Please, send important e-mails
on both addresses!=20
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