Re: Need help with these problems ASAP! Can someone help?

Hi,

This is what I have found.

1.	Balance the above equation
    2 H2O2(l) -> 2 H2O(l) + O2(g)

2.	How many liters of 02 can be made from 342 g of H202?
    Moles = 342 g / 34.01 g/mol
          = 10.06 mol of H2O2
    makes 5.03 mol of O2
    Volume = 5.03 mol x 32.00 g/mol / 1.428 g/L
           = 113 L

3.	The density of H202 is 1.463 g/mL, and the density of 02 is given above. How many liters of 02 can be made from 55.0 mL of H202?
    Moles = 55.0 mL x 1.463 g/mL / 34.01 g/mol
          = 2.366 mol of H2O2
    makes 1.183 mol of O2
    Volume = 1.183 mol x 32.00 g/mol / 1.428 g/L
           = 26.5 L

4.	How many liters of 02 will form if 22.5 g H202 react?
Replace 342 g in question 2 and calculate the answer. I get 7.41 L.

Lance

--- In [email protected], "ginaevansgreer" <evagi3@...> wrote:
>
> Calculate the following: Show ALL work to receive credit. Place a box around your final answer.
> 
> The decomposition of H202 is represented by the equation below.
> Given: Density of 02 =1.428 g/L
> H202(l) -----------------------> H20(g) + 02 g)
> 1.	Balance the above equation
> 2.	How many liters of 02 can be made from 342 g of H202?
> 3.	The density of H202 is 1.463 g/mL, and the density of 02 is given above. How many liters of 02 can be made from 55.0 mL of H202? 
> 4.	How many liters of 02 will form if 22.5 g H202 react? 
> 
> Please e-mail me at evagi3@...
> 
> Thanks!
>




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