Re: LAhE = lo broda be ?

la and cusku di'e

> xorxes:
> > Can we say that for every LAhE there is some broda that
> > can replace it so that {LAhE ko'a} = {lo broda be ko'a}?
> 
> PA1 LAhE ko'a = PA1 broda be ko'a

Right.

> > lu'i ko'a = lo selcmi be ko'a
[...] 
> > If this is so, then understanding the interaction of LAhEs and
> > quantifiers is relatively easy and there are no additional
> > decisions to make. 
> 
> Right.

But notice that this means {lu'i ko'a} is a set that includes ko'a
but does not necessarily exclude anything else.

If we want the set that has ko'a and only ko'a as a member, we
can't use {selcmi}. If we use a broda that means "x1 has x2 as its 
only member", then we can't use it for {lu'i ko'a e ko'e} to
get {ko'a ce ko'e}...

mu'o mi'e xorxes


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