Re: publish_parts and table of contents?

Thanks for your help on this.

This is *way* trickier than it looks, with all due respect. Clocked in
almost two days on this so far.

Just trying to get the table of contents separate from html_body.
Seriously considering adding ..contents:: to the source, building HTML and
ripping out the ToC via LXML.

Love reStructuredText and docutils (been having quite a few internal
successes lately), but this particular task feels like going against the
grain.

On July 21, 2017 at 3:39:58 PM, Guenter Milde via Docutils-users (
[email protected]) wrote:

On 2017-07-21, Tony Narlock wrote:

> So here is where I am:
> https://gist.github.com/tony/1a03b7668c9e33672f4465dd63c6076b

No time to look.

> On July 20, 2017 at 11:54:07 AM, Guenter Milde via Docutils-users (
> On 2017-07-20, Tony Narlock wrote:
>> On July 19, 2017 at 5:27:15 PM, Guenter Milde via Docutils-users (

>> ...


> > I suppose rather than messing with "parts", you can use the publish_*
> > functions in a wrapper script:
>
> > Don't use ``.. contents..`` in the source.
>
> > 1. Parse the rst source with publish_doctree()
>
> > Returns a doctree object.
>
>
> > 2. Export doctree to HTML with publish_from_doctree()

Does this work?

Yes, this just gives CSS + HTML for way more than I need. Am I supposed to
see anything special in the HTML or are you just checking that
publish_doctree+publish_from_doctree works (it does).

Way more than html_body (all I need, aside from ToC). And I’m not sure what
I can do with this content?




> > 3. Run the toc-generating transform on the doctree.
> > Returns a "toc doctree".

> Where would it be?

In docutils/transforms/parts.py



> Am I applying the transform correctly in the paste?

>> 4. Export the "toc doctree" with publish_from_doctree().

> Assuming I’m running the transform correctly, I see no difference in the
> output.

So I suppose you don't apply it correctly.

The idea is to collect generate a TOC by travelling over the doctree in
the same manner as it is done by the "Contents" transform.

Therefore, it should be possible to use
docutils.transforms.parts.Contents.build_contents() and pass it the
startnode of the doctree returned by "publish_parts".

>> This is just an idea, not tested and detailled.

Günter



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