Re: Defaulting to current directory

Yuval Oren wrote:

> What should the following Java code do if run in the same directory as=20
> doc.xml and doc.dtd? Should it be able to find doc.dtd?

[...]

> reader.parse(new InputSource(new FileInputStream(=93doc.xml=94)));

I would personally assume, that you have to use

     InputSource isource =3D new InputSource(new FileInputStream("doc.xml=
"));
     isource.setSystemId("doc.xml");
     reader.parse(isource);

because otherwise there is no such thing like a "base URI".


> Case 2 =96 JAXP:
>=20
> SAXParser parser =3D ...;
>=20
> parser.parse(new FileInputStream(=93doc.xml=94), new DefaultHandler());

In that case, I believe that

     parser.parse(new File("doc.xml"), new DefaultHandler());

will do the same, because this is implicitly creating an InputSource like=
 above.


Jochen


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