Re: Default Attributes and XSD

Hey Marko,

First it's useful to keep in mind that XSDs are not DTDs - most
particularly, DTDs have no notion of local declarations.

This being the case, what you are asking is a tall order in the general
case - for any (conformant) XSD.

It might not be so bad, however, for a particular XSD, if it happens to
follow coding conventions making it more like a DTD (and simplifying the
problem of matching attributes to their definitions). The approach would
probably be to reduce your XSD with a filter (XSLT) into what would
constitute essentially a lookup table for your attribute defaults, then
reference that from your main XSLT.

Note this is not specifically a Saxon question, or answer.

Good luck,
Wendell


On Thu, Mar 11, 2021 at 9:14 AM Marko Hedler <[email protected]> wrote:

> Hello everyone,
>
> using XSLT with SaxonEE 10.3, I want all default attribute values from a
> schema-valid XML instance to be expanded, but the XSLT-Transformation
> itself must not be schema-ware.
>
> I would like to have the same behavior as transforming a DTD-valid XML
> instance with Saxon.
>
> Any suggestions? Thanks in advance
>
> Marko
> _______________________________________________
> saxon-help mailing list archived at http://saxon.markmail.org/
> [email protected]
> https://lists.sourceforge.net/lists/listinfo/saxon-help



-- 
...Wendell Piez... ...wendell -at- nist -dot- gov...
...wendellpiez.com... ...pellucidliterature.org... ...pausepress.org...
...github.com/wendellpiez... ...gitlab.coko.foundation/wendell...

_______________________________________________
saxon-help mailing list archived at http://saxon.markmail.org/
[email protected]
https://lists.sourceforge.net/lists/listinfo/saxon-help