EXSLT format-date
Tomas Studva <[email protected]>
| Newsgroups | gmane.text.xml.xalan.java.user |
|---|---|
| Message-ID | <[email protected]> |
Hi,
I want to format date with an exslt "format-date" XPath function. When I
call this:
<xsl:variable name="datePattern">dd.MM.yyyy. 'o' HH:mm</xsl:variable>
<xsl:value-of select="date:format-date('2009-08-12T12:51:51.625+02:00',
$datePattern)" />
the output is "12.08.2009. o 00:00".
Please can you explain why the printed time is 00:00? I want to print the
time not 00:00. Am I missing something?
Tomas Studva
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