Re: How to achieve in xslt equivalent to xs:any in xerces

[email protected] wrote on 11/30/2009 11:28:36 AM:

> > As we have xs:any in xerces for any namespace usage , how do I
> > achieve in xslt ? I could not find any construct in xsl as we have
> > in schema language.
>
> XSLT 1.0 and XPath 1.0 are not schema-aware. (That was added in the
> 2.0 version of these, which Xalan does not yet support.)
>
> If you want to match names without looking at the namespace, you can
> use wildcard QNames such as *:foo, or match on a wildcard and then
> qualify that with a predicate.

I believe that form [1] has only been supported since XPath 2.0. Pretty
sure XPath 1.0 [1] only allows foo:* wildcards (but not *:foo).

Thanks.

[1] http://www.w3.org/TR/xpath20/#prod-xpath-NameTest
[2] http://www.w3.org/TR/xpath#NT-NameTest

Michael Glavassevich
XML Parser Development
IBM Toronto Lab
E-mail: [email protected]
E-mail: [email protected]