Re: [xquery-talk] Issues with recursive fn:transform

I have got the recursive function to work by simplifying the call to
eliminate the accumulator.
I think the error message is an issue. I shouldn't have got that.


On Mon, Nov 16, 2020 at 11:07 AM Ihe Onwuka <[email protected]> wrote:

> Below is a recursive fn:transform function.
> Takes 2 arguments - the XML and the accumulator and recursively calls a
> translator.xsl to generate a translation of the XML into the next version.
> That's what is supposed to happen, it infinitely loops because the next
> version of the XML is being generated so the base case is never true -
> can't see a reason why that should happen but for now I will settle for
> hopefully understanding something more straightforward
>
>    <xsl:function name="local:x" as="element()+">
>       <xsl:param name="currentVersion" as="element()"/>
>       <xsl:param name="accum" as="element()+"/>
>       <xsl:sequence select="if (namespace-uri($currentVersion/*) =>
> contains($finalTarget))
>                             then ($currentVersion,$accum)
>                             else local:x(fn:transform(map {
>                                                        'stylesheet-node' :
>  doc(''),
>                                       'source-node'     :  $currentVersion
>                                               })?output/*,
>                         $accum)"/>
>    </xsl:function>
>
> I have used the old doc('') trick to pass the current stylesheet (the name
> is translator.xsl) to the recursive call but that is not the value supplied
> as the first argument of local:x but the error message says it is
>
> XPTY0004  The required item type of the first argument of local:x() is
> element(); the
>   supplied value doc(.../translator.xsl) does not match. The supplied
> value is a document node
>

_______________________________________________
[email protected]
http://x-query.com/mailman/listinfo/talk