Re: with XPath 1.0, select all following sibling elements of name "foo" up to the first non-"foo" element

Would something like the following work for you?

   following-sibling::foo intersect
   following-sibling::*[not(self::foo)][1]/preceding-sibling::foo

. . . . . . . Ken

At 2021-02-18 01:32 +0000, Wolfhart Totschnig 
[email protected] wrote:
>Content-Transfer-Encoding: 8bit
>
>Dear list,
>
>I am facing an XPath problem for which I cannot find the solution. I 
>want to select all following sibling elements of name "foo" up to 
>the first non-"foo" element. So, in the following case, the first 
>two <foo> elements should be selected:
>
><foo/>
><foo/>
><bar/>
><foo/>
>
>In the following case, all three <foo> elements should be selected:
>
><foo/>
><foo/>
><foo/>
>
>And in the following case, nothing should be selected:
>
><bar/>
><foo/>
><foo/>
>
>I came up with the following non-working approach:
>
>             <xsl:choose>
>                 <xsl:when test="not(following-sibling::*[not(self::foo)])">
>                     <xsl:value-of select="following-sibling::*"/>
>                 </xsl:when>
>                 <xsl:otherwise>
>                     <xsl:value-of 
> select="following-sibling::*[not(self::source)][1]/preceding-sibling::*[self::source][preceding-sibling::current()]"/>
>                 </xsl:otherwise>
>             </xsl:choose>
>
>That is, test whether there are non-"foo" following siblings. If 
>there are none, take all following siblings. If there are, go 
>forward to the first non-"foo" sibling, and from there go backwards, 
>taking all the "foo" siblings up to the current node.
>
>But this does not work. Apparently, the expression 
>"preceding-sibling::current()" is not a valid construct. So what is 
>the correct way to do what I have in mind (or a simpler solution, if 
>there is one). Please note that this stylesheet needs to be executed 
>by a web browser, and so the solution has to remain within XPath 1.0.
>
>Thanks in advance for your help!
>Wolfhart
>


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