[LIP] problem with using Fortran routine in C..

Hello
       I am facing a weired problem in calling a fortran routine from 
c.  The fortran function in question is like this:-

subroutine fortran_fun(idtab, nx, x, nf, nh, nhd,  info, rinfo, fa, ga, 
ha, stats,iusr_size, iusr,rusr_size, rusr )
    implicit none
    external usrfgh
    external foo
    integer :: idtab, nx, nf, nh, nhd, info(20),itno
    integer :: iusr_size, rusr_size
    integer :: iusr(iusr_size)
    doubleprecision :: x(nx), rinfo(20+nx+nf)
    doubleprecision :: fa(nf), ha(nhd), stats(50)
    doubleprecision :: ga(nf,nx)
    doubleprecision :: rusr(rusr_size)
    character*128 :: fn
...........
...........

      While calling this function from another c with  debugger 
attached, gdb  output is:-

fortran_fun (idtab=13, nx=2, x=(), nf=1, nh=0, nhd=1, info=(0, 0, 0, 1, 
0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0), rinfo=(), fa=(), ga=(), 
ha=(), stats=Cannot access memory at address 0x0
) at isat_wrap.f90:8

         the varible *stats* is a pointer of _double_(fortran real*8 = c 
double) type and points to 50 valid blocks of memory allocated in C. (i 
have checkd it in c side and it is not NULL). It seems that the satck 
gets corrupted while calling the fortran function. How can I proceed?  I 
am using gcc 3.2 and intel fortran compiler.
         Any help is welcome.

Thanks in advance
Pavan

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