Re: filename renaming

Using this bit of bash and sed worked for me. It might choke on funky
characters, though

I used "Pictures" as my example directory:

for x in `ls Pictures/*` ; do
DIR_NAME=$(echo $x | sed -e 's|\([^/]*\)/.*|\1|')
FILE_NAME=$(echo $x | sed -e 's|[^/]*/\(.*\)|\1')
echo "${DIR_NAME}_${FILE_NAME}"
done

The first line iterates over all the file names in "Pictures" in the
form "Pictures/filename.jpg"
The second line uses sed to assign the variable DIR_NAME the name of
the directory
The third line uses sed to assign the variable FILE_NAME the name of the file
The fourth line just echoes the form of the filename you wanted. You'd
replace this line with a cp or mv, at your leisure. Remember, $x holds
the path to the file
The fifth line terminates the loop

This is quick and dirty; odds are there are programs out there you
could chain together to get the same results without resorting to
using sed.

Woogie

On Tue, Sep 20, 2011 at 4:38 PM, Normand Fisher <[email protected]> wrote:
> I'd like to have a script to rename groups of files by including the
> directory name in the revised filename.
>
> Ex:  in directory "A", I have files 1, 2, 3, 4, and 5.
> I would like to rename the files to A_1, A_2, A_3, A_4 and A_5.
>
> To do this, I have so far used the "mmv" command but I still have to
> type in the directory name for each batch.  Is there a way to capture
> the directory name and place it in a variable?
> I have looked at "pwd" but that gives me the whole path.
>
> I don't mind using command line but I am not a programmer.  Any
> suggestion is welcome.
>
> Normand
> --
> OCLUG general discussion list
> [email protected]
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>



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