Bug #71217 [Com]: foreach() with inline assignment doesn't keep references
[email protected] ("php at etc dot chkgo dot com")
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|---|---|
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Edit report at https://bugs.php.net/bug.php?id=71217&edit=1
ID: 71217
Comment by: php at etc dot chkgo dot com
Reported by: bugs dot php dot net at ss dot st dot tc
Summary: foreach() with inline assignment doesn't keep
references
Status: Open
Type: Bug
Package: Scripting Engine problem
Operating System: Linux, OSX
PHP Version: 7.0.1
Block user comment: N
Private report: N
New Comment:
Faced the same problem in a part of function results assignment right in foreach and changing iterated items by reference. Got unexpected behavior on PHP 7.0.0 and 7.0.1 but seemed working fine on 5.6. /Gentoo
So it was pretty much as described in the ticket. My vote.
Previous Comments:
------------------------------------------------------------------------
[2015-12-24 20:07:43] bugs dot php dot net at ss dot st dot tc
Description:
------------
When an inline assignment of array_expression is done right in foreach() statement, all further references to iterated array items seem to become their copies.
I believe both PHP 5.6 and 7 are affected, yet still they behave differently.
Tested on PHP 5.6.12, 5.6.16, 7.0.0, 7.0.1.
Test script:
---------------
<?php
# source array
$source = [ 'subarray' => ['item' => 'old value ---'] ];
# $ref1 is assigned to $source right in the foreach()
foreach ( $ref1 = $source as &$subarray ) {
$subarray['item'] = 'NEW value';
echo $subarray['item'], PHP_EOL;
echo $ref1['subarray']['item'], PHP_EOL;
}
echo PHP_EOL;
# $ref2 is assigned to $source normally, as a separate operation
$ref2 = $source;
foreach ( $ref2 as &$subarray ) {
$subarray['item'] = 'NEW value';
echo $subarray['item'], PHP_EOL;
echo $ref2['subarray']['item'], PHP_EOL;
}
echo PHP_EOL;
########################################
# similar to $source array, but implemented using a function
function getSource() {
return [ 'subarray' => ['item' => 'old value ---'] ];
}
# $ref3 is assigned to result of getSource() right in the foreach()
foreach ( $ref3 = getSource() as &$subarray ) {
$subarray['item'] = 'NEW value';
echo $subarray['item'], PHP_EOL;
echo $ref3['subarray']['item'], PHP_EOL;
}
echo PHP_EOL;
# $ref4 is a "normal" reference to a result of getSource()
$ref4 = getSource();
foreach ( $ref4 as &$subarray ) {
$subarray['item'] = 'NEW value';
echo $subarray['item'], PHP_EOL;
echo $ref4['subarray']['item'], PHP_EOL;
}
Expected result:
----------------
both PHP 5 and 7:
NEW value
NEW value
NEW value
NEW value
NEW value
NEW value
NEW value
NEW value
Actual result:
--------------
PHP 7:
NEW value
old value ---
NEW value
NEW value
NEW value
old value ---
NEW value
NEW value
PHP 5:
NEW value
old value ---
NEW value
NEW value
NEW value
NEW value
NEW value
NEW value
------------------------------------------------------------------------
--
Edit this bug report at https://bugs.php.net/bug.php?id=71217&edit=1