Re: [PHP-DB] Resource id #5

On 27 Mar 2008, at 17:51, Richard Dunne wrote:
> Can someone explain how I can translate Resource id #5 which is what  
> I am getting from the code below?
>
> $result = mysql_query("Select answer from answers") or  
> die(mysql_error());
> $resultArray = explode(',',$result);
> for ($i=0;$i<sizeof($resultArray);$i++)
> {
> 	echo $resultArray[$i];
> }

For the love of $DEITY, please read the frickin' manual: http://php.net/mysql 
. You've been asking similar questions around this topic for the past  
few days and you clearly haven't moved forward in your understanding.

The mysql_query function returns a resource. If you print a resource  
you get the text "Resource id #n" where n is replaced with its ID. To  
make use of this resource you need to use functions like  
mysql_fetch_array, mysql_fetch_assoc or one of the many others  
detailed in, you guessed it, the manual. Try it, you might like it.

-Stut

-- 
http://stut.net/