Re: [PHP-DB] input field validation

hi,

*javascript function :

function isNumber(obj) {
	var len  = obj.value.length;
	var lastChar = obj.value.charAt(len-1);
	if( lastChar != '0' && lastChar != '1' && lastChar != '2' && lastChar
!= '3' && lastChar != '4' &&


	lastChar != '5' && lastChar != '6' && lastChar != '7' && lastChar !=
'8' && lastChar != '9' ) {
		obj.value = obj.value.substring(0, len-1);

	}

}

this is function use :
<input *onKeyUp='isNumber(this)' .... />

do not alert , but add alert
----
*		obj.value = obj.value.substring(0, len-1);
---
this line before

---
alert('this field only integer!');
*

----

add.
good luck
şahabettin akca (saho)
2008/5/11 arafat uddin <[email protected]>:
-------------------------
and
this database field data type select int (integer) ,
tinyint, int, bigint... or
if(gettype($_POST['field'])!="integer") // or if(intval($_POST['field'])==0)
or if(!intval($_POST['field']))
{
print"not integer";
location("header: xxxx.php");
#or
print"<meta http-equiv='refresh' content='0;url=xxxx.php'>";
}
else
{
....
}
2008/5/11 Yves Sucaet <[email protected]>:

> Allow me to point out that this is not database-related...
>
> This website should get you everything you want:
> http://www.acmesoffware.com/acme/ExamplesJS/jsExm_ValidateInteger.asp
>
> HTH,
>
> Yves
>
> ----- Original Message ----- From: "arafat uddin" <[email protected]>
> To: <[email protected]>
> Sent: Sunday, May 11, 2008 12:48 AM
> Subject: [PHP-DB] input field validation
>
>
>
>  hi,
> >  i want to input only integer in my field.if without integer any
> > input put in the field it will show warning messege.
> > such as "12 "will be accept
> > but "12sds" will not accept .
> > "fhe34" will not accept
> >
> >
> > plz help me by any javascript code.
> >
> > --
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> >
> >
> >
>
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>


-- 
şahabettin akca // saho