New Table Creation with PHP Variables

[email protected] ("Keith Spiller")
Newsgroups php.db
Message-ID <008B1179CE594EBEA03CB064801823D1@Dragon>
Hi,

I'm trying to join multiple tables to then create a new table from the 
query.  I've figured out that part, but some of the fields need to be 
evaluated and then compared to a php array to derive their data.  In this 
example I am trying to populate the field4 column (from the $product_name 
array) after evaluating the product_type value on each row.

CREATE TABLE $table[name]
SELECT field1, field2, field3,
IF(o.product_type='course', $product_name[$product_id], NULL) AS field4, 
field5, field6, field7
FROM table1 as a, table2 as o;

Is this possible?  Is there another way to accomplish this task?  Thanks for 
your help.

Keith
lmpx.com only provides a reader for public news (NNTP) servers. It is not affiliated with the servers or forums shown here and is not responsible for the content of articles, which is written by their respective authors.