New Table Creation with PHP Variables
[email protected] ("Keith Spiller")
| Newsgroups | php.db |
|---|---|
| Message-ID | <008B1179CE594EBEA03CB064801823D1@Dragon> |
Hi, I'm trying to join multiple tables to then create a new table from the query. I've figured out that part, but some of the fields need to be evaluated and then compared to a php array to derive their data. In this example I am trying to populate the field4 column (from the $product_name array) after evaluating the product_type value on each row. CREATE TABLE $table[name] SELECT field1, field2, field3, IF(o.product_type='course', $product_name[$product_id], NULL) AS field4, field5, field6, field7 FROM table1 as a, table2 as o; Is this possible? Is there another way to accomplish this task? Thanks for your help. Keith