Re: [PHP-DB] PHP Results on multiple pages

[email protected] (Chris)
Newsgroups php.db
Message-ID <[email protected]>
> This script do everything fine counting total records
> it display's 1 to 10 records on first page with numbers but
> second location where i want it to display Showing results 1 to 10 it shows
> 17 to 26 second it displays a link to Next but not working.

It takes roughly 20 secs to do a search? Perhaps that should also be 
looked at.

Try to narrow down your problem.

> // begin to show results set
> echo " found  $numrows results <p>";
> $count = 1 + $s;

Where does $s come from? What is it supposed to mean? (Name your 
variables properly).

> // now you can display the results returned
>  while ($row= mysql_fetch_array($result)) {
> 
>  $title = $row["sname"];
>  $url = $row["url"];
>  $message = $row["massage"];
> //&nbsp;<a href=\"$row['url']\">"$row['sname']</a><br />
> $row['massage']<br><hr>'\
> 
>  echo "$count.)&nbsp";
>  echo "<b><a href=\"$url\" target=\"_blank\">$title</a></b>";
>  echo "<br>";
>  echo "$message<br><hr height=12 color=lightblue><br>";
>  $count++;
> 
>  }
> 
> $currPage = (($s/$limit) + 1);
> 
> //break before paging
>  echo "<br />";
> 
>  // next we need to do the links to other results
>  if ($s>=1) { // bypass PREV link if s is 0
>  $prevs=($s-$limit);
>  print "&nbsp;<a href='{$_SERVER['PHP_SELF']}?s=$prevs&q=$var'> <<<
>  Prev 10</a>&nbsp&nbsp;";
>  }
> 
> // calculate number of pages needing links
> //  $s=intval($numrows/$limit);
>  $s=ceil($numrows/$limit);
> 
> 
> // $s now contains int of pages needed unless there is a remainder from
> division
> 
>  if ($numrows%$limit) {
>  // has remainder so add one page
>  $s++;
>  }

What is $s set to here when there's extra pages to display?

> // check to see if last page
>  if (!((($s+$limit)/$limit)==$s) && $s!=1) {

That's just too complicated to read. The first part seems redundant 
since you're calculating $s anyway, why re-do it?

// are there extra pages to display?
if ($s > 1) {
   echo "show extra pages";
}


>  // not last page so give NEXT link  $PHP_SELF &gt;&gt;
>  $news="$s+$limit";
> 
>  echo "&nbsp;<a href='{$_SERVER['PHP_SELF']}?s=$news&q=$var'>Next 10 >>>
> </a>";
> 
>  }
> 
> $a = $s+$limit;
>  if ($a > $numrows) { $a = $numrows; }
> $b = $s+1;
>  echo "<p>Showing results $b to $a of $numrows</p>";
> include ('footer.inc');
> ?>
> 
> I shall highly appreciate if anyone shall have a look at it
> and let me know where i am wrong.
> 
> Thank you.
> 
> 


-- 
Postgresql & php tutorials
http://www.designmagick.com/
lmpx.com only provides a reader for public news (NNTP) servers. It is not affiliated with the servers or forums shown here and is not responsible for the content of articles, which is written by their respective authors.