Re: [PHP-DB] Retrieving Image Location in MySQL
[email protected] (Bastien Koert)
| Newsgroups | php.db |
|---|---|
| Message-ID | <[email protected]> |
On Fri, Mar 6, 2009 at 1:06 PM, Joao Gomes Madeira <[email protected]>wrote: > Hi Sashi: > > You're incurring in this error because the headers for the page have > already been issued in the head section of your page. > When you issue the php header() function, it will generate an error. > > Anyway, you are storing a path to a file in the database. My question > is: do you want to put your images on a subfolder of your site, where > they will become acessible through regular URLS, or you want to keep > them private and only accessible by scripting? > > Cheers. > JP > > -----Original Message----- > From: Sashikanth Gurram <[email protected]> > To: [email protected] > Subject: Re: [PHP-DB] Retrieving Image Location in MySQL > Date: Fri, 06 Mar 2009 12:23:31 -0500 > > Dear all, > > I have been trying to retrieve the location of a image from database and > display the image in the browser using PHP. I have written a sort of > code for the purpose. All I am getting in my browser after using the > code is a long set of ASCII characters with the following warning > *Warning*: Cannot modify header information - headers already sent by > (output started at C:\wamp\www\mysqli.php:65) > in *C:\wamp\www\mysqli.php* on line *237 > * > I am herewith attaching my code. If anyone can point out the error or > give some kind of advice that would be really great. The location of the > image is stored in a table by the name IMAGE under the column name > Location and here in the code, the location is retrieved under the > varibale name $Location. > > thanks, > Sashi > > /<html> > <body> > <form action="mysqli.php" method="post"> > <br> > <div align="center"> > Building Name:<select name="name"> > <option value=""> Select a Building</option> > <option value="Agnew Hall">Agnew Hall</option> > <option value="Rector Field House">Rector Field House</option> > <option value="Richard B. Talbot Educational Resources > Center">Richard B. Talbot Educational Resources Center</option> > <option value="Robeson Hall">Robeson Hall</option> > <option value="Sandy Hall">Sandy Hall</option> > <option value="Saunders hall">Saunders hall</option> > <option value="Seitz Hall">Seitz Hall</option> > <option value="Shanks Hall">Shanks Hall</option> > <option value="Shultz Hall">Shultz Hall</option> > <option value="Skelton Conference Center">Skelton Conference > Center</option> > <option value="Williams Hall">Williams Hall</option> > <option value="Women's Softball Field">Women's Softball Field</option> > <option value="Wright House">Wright House</option> > </select> > </div> > <input type="submit" /> > </form> > <img src="mysqli.php?"> > > <?php > // Connects to your Database > $host="*******"; > $user="*****"; > $password="******"; > $dbname="*******"; > $cxn=mysqli_connect($host, $user, $password, $dbname) ; > if (!$cxn=mysqli_connect($host, $user, $password, $dbname)) > { > $error=mysqli_error($cxn); > echo "$error"; > die(); > } > else > { > echo "Connection established successfully"; > } > //Define the variables for Day and Month > $Today=date("l"); > $Month=date("F"); > $build=$_POST["name"]; > $low_speed=2.5; > $high_speed=4; > $hour=date("G"); > $minute=date("i"); > if ($minute>=00 && $minute<=14) > { > $minute=00; > } > elseif ($minute>=15 && $minute<=29) > { > $minute=15; > } > elseif ($minute>=30 && $minute<=44) > { > $minute=30; > } > else > { > $minute=45; > } > $times="$hour:$minute"; > $sql="SELECT buildingname, parking_lot_name, empty_spaces, distance, > round(distance/($low_speed*60),1) AS low_time, > round(distance/($high_speed*60),1) AS high_time, Location FROM > buildings, buildings_lots, parkinglots, occupancy2, Image where > (buildings.buildingcode=occupancy2.building AND > buildings.buildingcode=buildings_lots.building_code AND > parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND > parkinglots.parking_lot_code=occupancy2.parking_lot AND > Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build' AND > month='$Month' AND day='$Today' AND Time='$times'"; > $data = mysqli_query($cxn,$sql); > if (!$data=mysqli_query($cxn,$sql)) > { > $error=mysqli_error($cxn); > echo "$error"; > die(); > } > else > { > echo "<br>"; > echo "Query sent successfully"; > } > echo "<br>"; > echo "<h1> PARKING LOT INFORMATION <h1>"; > echo "<table border='1' cellspacing='5' cellpadding='2'>"; > echo "<tr>\n > <th>Building</th>\n > <th>Parking Lot</th>\n > <th>Estimated Number of Empty Spaces</th>\n > <th>Distance (Feet)</th>\n > <th>Estimated walking time to the building</th>\n > </tr>\n"; > while ($row=mysqli_fetch_array($data)) > { > extract($row); > $building = $row[0]; > $parking_lot = $row[1]; > $Number_of_Empty_Spaces = $row[2]; > $Distance = $row[3]; > $time_l = $row[4]; > $time_h=$row[5]; > $location=$row[6]; > echo "<tr>\n > <td>$building</td>\n > <td>$parking_lot</td>\n > <td>$Number_of_Empty_Spaces</td>\n > <td>$Distance</td>\n > <td>$time_h - $time_l mins</td>\n > <td>$location</td>\n > </tr>\n"; > } > echo "</table>\n"; > $err=1; > if ($img = file_get_contents($location, FILE_BINARY)) > { > if ($img = imagecreatefromstring($img)) $err = 0; > } > if ($err) > { > header('Content-Type: text/html'); > echo '<html><body><p style="font-size:9px">Error getting > image...</p></body></html>'; > } > else > { > header('Content-Type: image/jpeg'); > imagejpeg($img); > imagedestroy($img); > } > ?> > </body> > </html>/ > > Sashikanth Gurram wrote: > > Hello guys, > > > > Thanks to you all for your kind replies. I will try the steps and get > > back to you if I encounter more problems. > > > > Thanks, > > Sashi > > > > Fortuno, Adam wrote: > >> Matya, > >> > >> Ha, ha, ha! Thank you good friend. I did say I didn't try the code :-) > >> > >> AF> Please note, I haven't tried this. It just seems plausible. > >> > >> I apologize if I confused anyone. I just meant to show how the > >> parameter could help retrieve a picture. I wasn't too concerned with > >> the particulars. Hopefully the concept is sound. If not, please do > >> flame my note so no one attempts it. > >> > >> Be Well, > >> A- > >> > >> -----Original Message----- > >> From: Mattyasovszky Janos [mailto:[email protected]] Sent: Monday, March > >> 02, 2009 9:29 AM > >> To: [email protected] > >> Subject: Re: [PHP-DB] Retrieving Image Location in MySQL > >> > >> Fortuno, Adam írta: > >> > >> > >>> //Write a query to pull out the picture's path > >>> $sql = "SELECT path FROM Image WHERE ID = %s"; > >>> mysql_real_escape_string($value); > >>> > >> > >> Sorry, but this won't work, since you don't map the value of the > >> escaped $value to the %s, lets say with sprintf()... > >> > >> Regards, > >> Matya > >> > >> > > > > > > > -- > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ > Sashikanth Gurram > Graduate Research Assistant > Department of Civil and Environmental Engineering > Virginia Tech > Blacksburg, VA 24060, USA > > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > What I normally do is to use php to create the main page and then reference the image in the img tag like this <img src='get_image.php?id=1234'> where the 1234 is the image I want to fetch. Then that page just handles the image is something like <?php // database connection $conn = mysql_connect("localhost", "user", "password") OR DIE (mysql_error()); @mysql_select_db ($db, $conn) OR DIE (mysql_error()); $sql = "SELECT * FROM image WHERE image_id=".$_GET["id"]; $result = mysql_query ($sql, $conn); if (mysql_num_rows ($result)>0) { $row = @mysql_fetch_array ($result); $image_type = $row["image_type"]; $image = $row["image"]; Header ("Content-type: $image_type"); print $image; } ?> -- Bastien Cat, the other other white meat