Re: [PHP-DB] Retrieving Image Location in MySQL
[email protected] (Sashikanth Gurram)
| Newsgroups | php.db |
|---|---|
| Message-ID | <[email protected]> |
Hi,
Thanks a lot for the suggestion. It is working fine but there is some
problem. When I introduced the piece of code you have suggested into my
code, I am getting a space for the picture but nothing is there in that
space. It is just blank. I do not know the reason for this. Further,
this is the piece of code I have written to display the pic.
echo "<img src='$location' border='1' height='150' width='200'
alt='$build' >";
Any help would be greatly appreciated.
Thanks,
Sashi
mrfroasty wrote:
> Hello,
>
> Storing only location of the image in dB wouldnt be any different than
> other string/data retrieved from the dB.That means if you have something
> like this in html documents whereby $image_location comes from the dB
> It should work without ....header stuffs
>
> Example
> <img src="$image_location" border="1" height="150" width="200"
> alt="Image" ISMAP>
> P:S
> Replace $image_location with image location from your dB.
>
>
> GR
> Muhsin
>
>
>
> Sashikanth Gurram wrote:
>
>> Dear all,
>>
>> I have been trying to retrieve the location of a image from database
>> and display the image in the browser using PHP. I have written a sort
>> of code for the purpose. All I am getting in my browser after using
>> the code is a long set of ASCII characters with the following warning
>> *Warning*: Cannot modify header information - headers already sent by
>> (output started at C:\wamp\www\mysqli.php:65) in
>> *C:\wamp\www\mysqli.php* on line *237
>> *
>> I am herewith attaching my code. If anyone can point out the error or
>> give some kind of advice that would be really great. The location of
>> the image is stored in a table by the name IMAGE under the column name
>> Location and here in the code, the location is retrieved under the
>> varibale name $Location.
>>
>> thanks,
>> Sashi
>>
>> /<html>
>> <body>
>> <form action="mysqli.php" method="post">
>> <br>
>> <div align="center">
>> Building Name:<select name="name">
>> <option value=""> Select a Building</option>
>> <option value="Agnew Hall">Agnew Hall</option>
>> <option value="Rector Field House">Rector Field House</option>
>> <option value="Richard B. Talbot Educational Resources
>> Center">Richard B. Talbot Educational Resources Center</option>
>> <option value="Robeson Hall">Robeson Hall</option>
>> <option value="Sandy Hall">Sandy Hall</option>
>> <option value="Saunders hall">Saunders hall</option>
>> <option value="Seitz Hall">Seitz Hall</option>
>> <option value="Shanks Hall">Shanks Hall</option>
>> <option value="Shultz Hall">Shultz Hall</option>
>> <option value="Skelton Conference Center">Skelton Conference
>> Center</option>
>> <option value="Williams Hall">Williams Hall</option>
>> <option value="Women's Softball Field">Women's Softball
>> Field</option>
>> <option value="Wright House">Wright House</option>
>> </select>
>> </div>
>> <input type="submit" />
>> </form>
>> <img src="mysqli.php?">
>>
>> <?php
>> // Connects to your Database
>> $host="*******";
>> $user="*****";
>> $password="******";
>> $dbname="*******";
>> $cxn=mysqli_connect($host, $user, $password, $dbname) ;
>> if (!$cxn=mysqli_connect($host, $user, $password, $dbname))
>> {
>> $error=mysqli_error($cxn);
>> echo "$error";
>> die();
>> }
>> else
>> {
>> echo "Connection established successfully";
>> }
>> //Define the variables for Day and Month
>> $Today=date("l");
>> $Month=date("F");
>> $build=$_POST["name"];
>> $low_speed=2.5;
>> $high_speed=4;
>> $hour=date("G");
>> $minute=date("i");
>> if ($minute>=00 && $minute<=14)
>> {
>> $minute=00;
>> }
>> elseif ($minute>=15 && $minute<=29)
>> {
>> $minute=15;
>> }
>> elseif ($minute>=30 && $minute<=44)
>> {
>> $minute=30;
>> }
>> else
>> {
>> $minute=45;
>> }
>> $times="$hour:$minute";
>> $sql="SELECT buildingname, parking_lot_name, empty_spaces, distance,
>> round(distance/($low_speed*60),1) AS low_time,
>> round(distance/($high_speed*60),1) AS high_time, Location FROM
>> buildings, buildings_lots, parkinglots, occupancy2, Image where
>> (buildings.buildingcode=occupancy2.building AND
>> buildings.buildingcode=buildings_lots.building_code AND
>> parkinglots.parking_lot_code=buildings_lots.parking_lot_code AND
>> parkinglots.parking_lot_code=occupancy2.parking_lot AND
>> Buildings.BuildingCode=Image.BuildingCode) AND buildingname='$build'
>> AND month='$Month' AND day='$Today' AND Time='$times'";
>> $data = mysqli_query($cxn,$sql);
>> if (!$data=mysqli_query($cxn,$sql))
>> {
>> $error=mysqli_error($cxn);
>> echo "$error";
>> die();
>> }
>> else
>> {
>> echo "<br>";
>> echo "Query sent successfully";
>> }
>> echo "<br>";
>> echo "<h1> PARKING LOT INFORMATION <h1>";
>> echo "<table border='1' cellspacing='5' cellpadding='2'>";
>> echo "<tr>\n
>> <th>Building</th>\n
>> <th>Parking Lot</th>\n
>> <th>Estimated Number of Empty Spaces</th>\n
>> <th>Distance (Feet)</th>\n
>> <th>Estimated walking time to the building</th>\n
>> </tr>\n";
>> while ($row=mysqli_fetch_array($data))
>> {
>> extract($row);
>> $building = $row[0];
>> $parking_lot = $row[1];
>> $Number_of_Empty_Spaces = $row[2];
>> $Distance = $row[3];
>> $time_l = $row[4];
>> $time_h=$row[5];
>> $location=$row[6]; echo "<tr>\n
>> <td>$building</td>\n
>> <td>$parking_lot</td>\n
>> <td>$Number_of_Empty_Spaces</td>\n
>> <td>$Distance</td>\n
>> <td>$time_h - $time_l mins</td>\n
>> <td>$location</td>\n
>> </tr>\n";
>> }
>> echo "</table>\n";
>> $err=1;
>> if ($img = file_get_contents($location, FILE_BINARY))
>> {
>> if ($img = imagecreatefromstring($img)) $err = 0;
>> }
>> if ($err)
>> {
>> header('Content-Type: text/html');
>> echo '<html><body><p style="font-size:9px">Error getting
>> image...</p></body></html>';
>> }
>> else
>> {
>> header('Content-Type: image/jpeg');
>> imagejpeg($img);
>> imagedestroy($img);
>> }
>> ?>
>> </body>
>> </html>/
>>
>> Sashikanth Gurram wrote:
>>
>>> Hello guys,
>>>
>>> Thanks to you all for your kind replies. I will try the steps and get
>>> back to you if I encounter more problems.
>>>
>>> Thanks,
>>> Sashi
>>>
>>> Fortuno, Adam wrote:
>>>
>>>> Matya,
>>>>
>>>> Ha, ha, ha! Thank you good friend. I did say I didn't try the code :-)
>>>>
>>>> AF> Please note, I haven't tried this. It just seems plausible.
>>>>
>>>> I apologize if I confused anyone. I just meant to show how the
>>>> parameter could help retrieve a picture. I wasn't too concerned with
>>>> the particulars. Hopefully the concept is sound. If not, please do
>>>> flame my note so no one attempts it.
>>>>
>>>> Be Well,
>>>> A-
>>>>
>>>> -----Original Message-----
>>>> From: Mattyasovszky Janos [mailto:[email protected]] Sent: Monday, March
>>>> 02, 2009 9:29 AM
>>>> To: [email protected]
>>>> Subject: Re: [PHP-DB] Retrieving Image Location in MySQL
>>>>
>>>> Fortuno, Adam Ãrta:
>>>>
>>>>
>>>>
>>>>> //Write a query to pull out the picture's path
>>>>> $sql = "SELECT path FROM Image WHERE ID = %s";
>>>>> mysql_real_escape_string($value);
>>>>>
>>>>>
>>>> Sorry, but this won't work, since you don't map the value of the
>>>> escaped $value to the %s, lets say with sprintf()...
>>>>
>>>> Regards,
>>>> Matya
>>>>
>>>>
>>>>
>>>
>>
>
>
>
--
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA