Re: [PHP-DB] Please help a newbie
[email protected] (mrfroasty)
| Newsgroups | php.db |
|---|---|
| Message-ID | <[email protected]> |
Hello,
May be try something like this:
$query1=
CREATE TABLE contacts(
id int(16) NOT NULL auto_increment,
phone varchar(15) NOT NULL,
name varchar(15) NOT NULL,
address varchar(15) NOT NULL,
PRIMARY KEY (id)
);
$query2 = "INSERT INTO contacts VALUES ('NULL','$phone', '$name',
'$address')";
P:S
id incremented automatically by MYSQL now
GR
mrfroasty
Rij wrote:
> Hello,
>
> I am new to the world of PHP and MySQL. My objective is to create a
> table, insert values in it and read it back.
>
> Here's the partial code to create a table from a PHP file:
>
> if (!$table_exists) {
> $query="CREATE TABLE contacts (id int(20) NOT NULL, name
> varchar(15) NOT NULL, address varchar(15),PRIMARY KEY(id)
> if (mysql_query($query, $con)) echo "Table contacts created";
> else die('Unable to create table : '.mysql_error());
> }
>
>
> I input the values from a HTML form. Here is the partial code.
> $phone = $_POST['phone'];
> $name = $_POST['name'];
> $address = $_POST['address'];
> $query = "INSERT INTO contacts VALUES ('$phone', '$name', '$address')";
> if (mysql_query($query, $con)) echo "Values inserted";
> else die('Unable to create table : '.mysql_error());
>
>
> Now the problem that I am facing is that when I make my first insert,
> the id field shows a garbage value and not the number that I entered.
> Subsequent entries into the table show up just fine. It's only the
> first one.
>
> What am I doing wrong?
>
> Thanks, Rij
>
>
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