Re: [PHP-DB] Random pick

Hi,
$req_user_level is a MySql return result and I am trying to utilize  
shortened code to evaluate whither $req_user_level == 0 || 1 || 2 ||  
3 || 4 || 5 || 6 || 7 || 8 || 9, if it matches a number, return the  
text associated with that number.
"Guest" || "Regular User" || "Intl. User" || "Contractor" ||  
"Employee" || "Sales" || "Investor" || "Human Resources" ||  
"Administrator";

Karl


On Jan 25, 2010, at 1:31 PM, Olavi Ivask wrote:

> Hi,
>
> did you mean something like this?
>
> $level_names = array("Guest", "Regular User", "Intl. User",  
> "Contractor", "Employee",
> 			"Sales", "Investor", "Human Resources", "Administrator");
>
> $user_level = $level_names[$req_user_level];
>
> Regards,
> Olavi Ivask
>
>
> On Jan 25, 2010, at 9:13 PM, Karl DeSaulniers wrote:
>
>> Hello List,
>> Trying to learn the right way to code this line.
>> Can anyone tell me if I am doing this the right way?
>>
>> if $req_user_level == 0 || 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 ||  
>> 9 ? "Guest" || "Regular User" || "Intl. User" || "Contractor" ||  
>> "Employee" || "Sales" || "Investor" || "Human Resources" ||  
>> "Administrator";
>>
>> I am wanting to stray from the if(foo == bar) { routine. ;)
>>
>> Thanks,
>>
>> Karl DeSaulniers
>> Design Drumm
>> http://designdrumm.com
>>
>

Karl DeSaulniers
Design Drumm
http://designdrumm.com