Re: [PHP-DB] Random pick

Don't you like my solution?

Regards,
Olavi

On Jan 25, 2010, at 9:39 PM, Karl DeSaulniers wrote:

> Hi,
> $req_user_level is a MySql return result and I am trying to utilize  
> shortened code to evaluate whither $req_user_level == 0 || 1 || 2 ||  
> 3 || 4 || 5 || 6 || 7 || 8 || 9, if it matches a number, return the  
> text associated with that number.
> "Guest" || "Regular User" || "Intl. User" || "Contractor" ||  
> "Employee" || "Sales" || "Investor" || "Human Resources" ||  
> "Administrator";
>
> Karl
>
>
> On Jan 25, 2010, at 1:31 PM, Olavi Ivask wrote:
>
>> Hi,
>>
>> did you mean something like this?
>>
>> $level_names = array("Guest", "Regular User", "Intl. User",  
>> "Contractor", "Employee",
>> 			"Sales", "Investor", "Human Resources", "Administrator");
>>
>> $user_level = $level_names[$req_user_level];
>>
>> Regards,
>> Olavi Ivask
>>
>>
>> On Jan 25, 2010, at 9:13 PM, Karl DeSaulniers wrote:
>>
>>> Hello List,
>>> Trying to learn the right way to code this line.
>>> Can anyone tell me if I am doing this the right way?
>>>
>>> if $req_user_level == 0 || 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 ||  
>>> 9 ? "Guest" || "Regular User" || "Intl. User" || "Contractor" ||  
>>> "Employee" || "Sales" || "Investor" || "Human Resources" ||  
>>> "Administrator";
>>>
>>> I am wanting to stray from the if(foo == bar) { routine. ;)
>>>
>>> Thanks,
>>>
>>> Karl DeSaulniers
>>> Design Drumm
>>> http://designdrumm.com
>>>
>>
>
> Karl DeSaulniers
> Design Drumm
> http://designdrumm.com
>