Re: [PHP-DB] Random pick

Yes, $req_user_level is an int between 0 and 9.

Yes, the other code worked great.
Thank you for your response though.
That is definitely a good way to cross check.
Thanks again for your responses.
Best,

Karl


On Jan 25, 2010, at 2:24 PM, Peter Beckman wrote:

> On Mon, 25 Jan 2010, Karl DeSaulniers wrote:
>
>> Thank you for this as well.
>> Question? What part is "in_array" playing?
>> Is it comparing $req_user_level to array()?
>> Because the text "Guest", etc.. is not in $req_user_level on the  
>> database.
>> In other words, is it checking the value of $req_user_level to see  
>> if "Guest" is in it?
>
>  Sorry, I missed the question mark.  in_array isn't appropriate  
> here.  The
>  previous poster has it right, assuming $req_user_level is an  
> integer of
>  0..9.
>
>  $levels = array("Guest", "Regular User", 'Intl. User', ...)
>  // the array is   0    ,      1        ,       2     , ...)
>
>  Going a little further:
>
>     if (!empty($levels[$req_user_level])) {  // is both set and  
> doesn't evaluate to false
>         echo "The user is a {$levels[$req_user_level]}.\n";
>     } else {
>         //  The $req_user_level was not a valid level.
>         echo "The returned req_user_level was not valid.\n";
>     }
>
>  Which would output, if $req_user_level was 1 (one):
>
>     The user is a Regular User.
>
>  Then you know you have a valid user level.  Careful though --  
> sometimes 0
>  will be returned on a failure, depending on your SQL.
>
> Beckman
> ---------------------------------------------------------------------- 
> -----
> Peter Beckman                                                   
> Internet Guy
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Karl DeSaulniers
Design Drumm
http://designdrumm.com